phpunit mock - 将返回对象

Question

使用phpunit mock对象,我有一个返回对象的方法.

你如何使用expected/method/will方法编写代码？

即

 ->will($this->returnValue('Class_Name'));

Answer 1

创建对象,并使用该returnValue()函数返回它.例如:

$myObject = new RandomObject();
$myFactory = $this->getMock('ObjectFactory', array('getRandomObject'));
$myFactory->expects($this->any())->method('getRandomObject')->will($this->returnValue($myObject);

$this->assertInstanceOf('RandomObject', $myFactory->getRandomObject());

这将通过.

您还可以将该对象创建为模拟本身并传递模拟.