use*_*686 10 excel vba excel-vba
我想让我的自定义VBA函数只接受单单元格参数.这样做的正确方法是什么:
myCell as Cell要么:
myRange as Range默认情况下传递并获取(如何?)左上角的单元格?InC*_*ext 18
如果您选择多个单元格,该函数将退出:
Function AcceptOneCell(rng As Range)
If (rng.Cells.Count > 1) Then
AcceptOneCell = "Only allow 1 cell"
Exit Function
End If
' your code here
End Function
Run Code Online (Sandbox Code Playgroud)
假设您的用户将输入具有多个列和行的范围,您可以执行以下检查以退出该函数,如果这是您在问题中的意思...
Function myFunction(ByRef myCell as Range) as SomeDataType_of_your_choice
Dim numRow as Long, numCol as Long
numRow = myCell.Columns.Count
numCol = myCell.Rows.Count
If numRow > 1 or numCol > 1 Then
MsgBox "Only one cell is accepted"
Exit Function
Else
'-- do other stuff you want to do here
End If
End Function
Run Code Online (Sandbox Code Playgroud)
| 归档时间: |
|
| 查看次数: |
57177 次 |
| 最近记录: |