将参数传递给BroadcastReceiver

Question

我正在尝试将一个int值从我的Service传递给CallReceiver类,不幸的是CallReceiver.value总是等于0,即使在设置了另一个值之后也是如此.当我试图将它作为参数传递给构造函数时,情况完全相同,因此使用从service调用的setter方法.真的没有办法传递任何数据吗？

服务:

SharedPreferences settings = getSharedPreferences("SETTINGS", 0);
    int value = settings.getInt("value1", 0); // here the correct value is present, not 0.
    CallReceiver mCallReceiver = new CallReceiver();
    CallReceiver.value = value;  

接收器:

public class CallReceiver extends BroadcastReceiver  {

public int value;

public CallReceiver(int value)  {
    this.value = value;
}

public CallReceiver()   {

}


@Override
public void onReceive(Context context, Intent intent) {


            Log.v("value", String.valueOf(value)); // here "value" = 0.


        }

     }

Answer 1

您的CallReceiver mCallReceiver=new CallReceiver();实例不用于接收意图.相反,Android每次都会创建新实例.0是未初始化的整数变量的默认值.

要确保发生这种情况,请为您的value字段指定一些默认值:

public class RReceiver extends BroadcastReceiver {
    public int value=5;
    //...
}

而你的价值总是等于5.

至于传递数据BroadcastReceiver,将其添加为Intent您正在广播的额外内容:

//in your service
Intent broadcastedIntent=new Intent(this, CallReceiver.class);
broadcastedIntent.putExtra("VALUE", 100500);
sendBroadcast(broadcastedIntent);

然后,在你的CallReceiver:

@Override
public void onReceive(Context context, Intent intent) {
    int value=intent.getIntExtra("VALUE", 0);
}