问题列表 - 第47588页

我正在寻找一种在编辑时插入文件名/路径内联的方法.类似于内联ido风格的文件选择将是完美的.那里有类似的东西吗？

如果问题看起来很奇怪,我道歉.我正在调试我的代码,这似乎是问题,但我不确定.

谢谢!

如果我在我的3个模型模型的任何记录上单击destroy,则用户将被注销.我正在使用Devise和Ominauth.

#This logs out a user 
def destroy
    @rating = Rating.find(params[:id])
    @rating.destroy
  end


Started POST "/ratings/29" for 192.168.1.103 at 2011-02-26 20:11:45 +0000
  Processing by RatingsController#destroy as HTML
  Parameters: {"id"=>"29"}
  User Load (0.5ms)  SELECT `users`.* FROM `users` WHERE `users`.`id` = 2 LIMIT 1
  Rating Load (0.3ms)  SELECT `ratings`.* FROM `ratings` WHERE `ratings`.`id` = 29 LIMIT 1
  SQL (0.0ms)  BEGIN
  AREL (0.5ms)  DELETE FROM `ratings` WHERE `ratings`.`id` = 29
  SQL (2.7ms)  COMMIT



Request

Parameters:

None
Show session dump

session_id: "16a92c418fdfa8966b60b09e76346443"
Show env …

以下每个数组定义之间有什么区别.

var myArray = [];
var myArray = {};
var myArray = new Array();

我正在尝试将对象持久化到数据库.继续获取'列ID不能接受空值错误'.我的对象看起来像这样:

    @Entity
public class TestTable {
    @Id
    @GeneratedValue(strategy = GenerationType.AUTO)
    private Integer id = 0;

    @Column(nullable=false, length=256)
    private String data = "";

    public Integer getId() {
        return id;
    }

    public void setId(Integer id) {
        this.id = id;
    }

    public String getData() {
        return data;
    }

    public void setData(String data) {
        this.data = data;
    }

}

我的坚持功能:

public static synchronized boolean persistObject(Object obj){
        boolean success = true;
        EntityManager em = null;
        EntityTransaction tx = null;
        try{
            em = getEmf().createEntityManager();
            tx = …

是否可以通过编程方式将图像添加到节点？

我想在Windows XP上安装rackamole:

S:\development\DevKit>gem install rackamole
Temporarily enhancing PATH to include DevKit...
Building native extensions.  This could take a while...
ERROR:  While executing gem ... (Errno::EACCES)
    Permission denied - S:/development/Ruby/lib/ruby/gems/1.9.1/gems/rackamole-0.4.0/...

我已经检查了许可:

S:\development\DevKit>notepad S:\development\Ruby\lib\ruby\gems\1.9.1\gems\rackamole-0.4.0\some.txt

并没有任何问题.

我该如何安装gem？

从我想要提取其路径的任何URL.

例如:

网址:https://stackoverflow.com/questions/ask 路径:问题/问题

这应该不难:

url[/(?:\w{2,}\/).+/]

但我认为我使用错误的模式'忽略这个'('？:' - 不起作用).什么是正确的方法？

这是我一直遇到的一个问题,我希望这里的某个人能够对此有所了解.

我有一个Android游戏加载一个GLSurfaceView谁的渲染器设置如下:

public class GameRenderer implements GLSurfaceView.Renderer
{
    public void onSurfaceCreated(GL10 gl, EGLConfig config)
    {
        BaseLib.init(); // Initializes the native code
    }

    public void onSurfaceChanged(GL10 gl, int width, int height)
    {}

    public void onDrawFrame(GL10 gl)
    {
        BaseLib.render(); // Call to native method to render/update the current frame
    }
}

视图是这样的:

public class GameView extends GLSurfaceView implements SurfaceHolder.Callback
{
    private GameRenderer _renderer;
    private GameListener _listener;

    public GameView(Context context)
    {
        super(context);
        this._renderer = new GameRenderer();
        setRenderer(this._renderer);
        this._listener = new GameListener();
        BaseLib.setListener(this._listener);
    } …

我在实践中阅读Java并发性,下面的例子来自于此.我的问题是这个参考逃脱是什么意思？会有什么问题？.这个引用是如何从doSomething(e)中逃脱的.

public class ThisEscape {
    public ThisEscape(EventSource source) {
        source.registerListener(
            new EventListener() {
                public void onEvent(Event e) {
                    doSomething(e);
                }
            }
        );
    }
}

这是如何解决这个问题的

public class SafeListener {
    private final EventListener listener;
    private SafeListener() {
        listener = new EventListener() {
            public void onEvent(Event e) {
                doSomething(e);
            }
        };
    }
    public static SafeListener newInstance(EventSource source) {
        SafeListener safe = new SafeListener();
        source.registerListener(safe.listener);
        return safe;
    }
}

编辑:

我试过以下的例子

public class Escape {
    public  Escape( Printer printer ){
        printer.print(new Escaper(){
            @Override …