在修改历史状态时是否可以订阅某些事件?怎么样?
我搜索谷歌和这个论坛,我找到了这个解决方案
sth=os.path.abspath('/home/artur/Desktop')
sys.path.append(sth)
os.environ['DJANGO_SETTINGS_MODULE'] = 'project_name.settings'
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即使我的编辑器提供对import语句的支持,每个想法似乎都可以.当我尝试导入我的模型时,我得到了这个
Traceback (most recent call last):
File "email.py", line 12, in <module>
from app_name.models import *
File "app's models models.py", line 1, in <module>
from django.db import models
File "/usr/local/lib/python2.6/dist-packages/Django-1.2.5-py2.6.egg/django/db/models/__init__.py", line 5, in <module>
from django.db.models.query import Q
File "/usr/local/lib/python2.6/dist-packages/Django-1.2.5-py2.6.egg/django/db/models/query.py", line 9, in <module>
from django.db.models.fields import DateField
File "/usr/local/lib/python2.6/dist-packages/Django-1.2.5-py2.6.egg/django/db/models/fields/__init__.py", line 14, in <module>
from django import forms
File "/usr/local/lib/python2.6/dist-packages/Django-1.2.5-py2.6.egg/django/forms/__init__.py", line 14, in <module>
from widgets import *
File "/usr/local/lib/python2.6/dist-packages/Django-1.2.5-py2.6.egg/django/forms/widgets.py", line 9, in <module> …Run Code Online (Sandbox Code Playgroud) 这是我正在使用的命令:
appcfg.py download_app -A --application= appid
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输出:
/usr/local/bin/appcfg.py:42: DeprecationWarning: the sha module is deprecated; use the hashlib module instead
os.path.join(DIR_PATH, 'lib', 'django_0_96'),
/Applications/GoogleAppEngineLauncher.app/Contents/Resources/GoogleAppEngine-default.bundle/Contents/Resources/google_appengine/google/appengine/tools/dev_appserver_login.py:33: DeprecationWarning: the md5 module is deprecated; use hashlib instead
import md5
Host: appengine.google.com
Fetching file list...
Email: [email]
Password for [email]:
Error 400: --- begin server output ---
Client Error (400)
The request is invalid for an unspecified reason.
--- end server output ---
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我的电子邮件/ pw是正确的.任何人都可以帮我翻译这个错误吗?
class Pair(models.Model):
first = models.ForeignKey(User, related_name='pair_first')
second = models.ForeignKey(User, related_name='pair_second')
class PairForm(forms.ModelForm):
class Meta:
model = Pair
fields = ('second',)
def clean(self):
first = None # how can I get first?
second = self.cleaned_data.get("second")
if (first == second):
raise ValidationError("You can't pair with yourself, silly.")
def pair_create(request):
if request.method == 'POST':
pair = Pair()
pair.first = request.user
form = PairForm(instance=pair, data=request.POST)
if form.is_valid():
form.save();
return HttpResponseRedirect(reverse('somewhere'))
else:
form = PairForm()
return render_to_response('something.html', {
'form': form,
}, context_instance=RequestContext(request))
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登录用户想要与另一个用户配对.它们显示为带下拉列表的表单.如果他们自己选择,则提出验证错误.
问题:在PairForm的clean(self) …
我有一个很好的Mac Pro 4核+超线程.是否有任何Intellij设置需要调整才能利用这一点?通过GUI,还是编辑Info.plist文件?
我对使GWT编译/执行更快更感兴趣.(我已经 localWorkers 4设定好了).
谢谢
#!/usr/bin/env perl
use warnings;
use 5.012;
say "no semicolon"
say "World";
say "World";
say "World";
say "World";
say "World";
# syntax error at ./perl1.pl line 7, near "say"
# Execution of ./perl1.pl aborted due to compilation errors.
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.
#!/usr/bin/env perl
use warnings;
use 5.012;
my $character = "\x{ffff}";
say "Hello";
say "Hello";
say "Hello";
say "Hello";
say "Hello";
# Unicode non-character 0xffff is illegal for interchange at ./perl1.pl line 5.
# Hello
# Hello
# Hello
# Hello
# Hello …Run Code Online (Sandbox Code Playgroud) 在使用Steak,Capybara和RSpec的Rails 3应用程序中,如何测试页面标题?
我不清楚框架的链接是什么以及如何做到这一点.这听起来只是连接框架的弱点,但我认为不是.任何帮助,将不胜感激.谢谢!
我想用C#在Windows应用程序中编码和解码jpg文件.
我怎么能这样做?
我有以下基于asynctask的代码块.我试图通过返回LoadFeed()返回List变量,并且doInBackground的返回类型是String.如果我将doInBackground的返回类型从String更改为List,那么我会收到错误
"The return type is incompatible with AsyncTask<String,Void,String>.doInBackground(String[])"
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我该如何解决这个错误?请帮忙
谢谢,
private class DispData extends AsyncTask<String, Void, String> {
private final ProgressDialog dialog = new ProgressDialog(MessageList.this);
// can use UI thread here
protected void onPreExecute() {
dialog.setMessage("Fetching scores...");
dialog.show();
}
// automatically done on worker thread (separate from UI thread)
protected String doInBackground(final String... args) {
return loadFeed();
}
// can use UI thread here
protected void onPostExecute(final List<String> result) {
if (dialog.isShowing()) {
dialog.dismiss();
}
adapter =
new ArrayAdapter<String>(MessageList.this,R.layout.row,result);
MessageList.this.setListAdapter(adapter); …Run Code Online (Sandbox Code Playgroud) django ×2
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