问题列表 - 第47587页

40
推荐指数
2
解决办法
5万
查看次数

django外部脚本ImportError:没有名为Utils的模块

我搜索谷歌和这个论坛,我找到了这个解决方案

sth=os.path.abspath('/home/artur/Desktop')
sys.path.append(sth)
os.environ['DJANGO_SETTINGS_MODULE'] = 'project_name.settings'
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即使我的编辑器提供对import语句的支持,每个想法似乎都可以.当我尝试导入我的模型时,我得到了这个

Traceback (most recent call last):
  File "email.py", line 12, in <module>
    from app_name.models import *
  File "app's models models.py", line 1, in <module>
    from django.db import models
  File "/usr/local/lib/python2.6/dist-packages/Django-1.2.5-py2.6.egg/django/db/models/__init__.py", line 5, in <module>
    from django.db.models.query import Q
  File "/usr/local/lib/python2.6/dist-packages/Django-1.2.5-py2.6.egg/django/db/models/query.py", line 9, in <module>
    from django.db.models.fields import DateField
  File "/usr/local/lib/python2.6/dist-packages/Django-1.2.5-py2.6.egg/django/db/models/fields/__init__.py", line 14, in <module>
    from django import forms
  File "/usr/local/lib/python2.6/dist-packages/Django-1.2.5-py2.6.egg/django/forms/__init__.py", line 14, in <module>
    from widgets import *
  File "/usr/local/lib/python2.6/dist-packages/Django-1.2.5-py2.6.egg/django/forms/widgets.py", line 9, in <module> …
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django

3
推荐指数
1
解决办法
5541
查看次数

无法下载GAE源代码

这是我正在使用的命令:

appcfg.py download_app -A --application= appid
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输出:

/usr/local/bin/appcfg.py:42: DeprecationWarning: the sha module is deprecated; use the hashlib module instead
  os.path.join(DIR_PATH, 'lib', 'django_0_96'),
/Applications/GoogleAppEngineLauncher.app/Contents/Resources/GoogleAppEngine-default.bundle/Contents/Resources/google_appengine/google/appengine/tools/dev_appserver_login.py:33: DeprecationWarning: the md5 module is deprecated; use hashlib instead
  import md5
Host: appengine.google.com
Fetching file list...
Email: [email]  
Password for [email]: 
Error 400: --- begin server output ---

Client Error (400)
The request is invalid for an unspecified reason.
--- end server output ---
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我的电子邮件/ pw是正确的.任何人都可以帮我翻译这个错误吗?

google-app-engine

1
推荐指数
1
解决办法
2106
查看次数

Access实例从clean(self)方法传递给ModelForm

class Pair(models.Model):
    first = models.ForeignKey(User, related_name='pair_first')
    second = models.ForeignKey(User, related_name='pair_second')

class PairForm(forms.ModelForm):
    class Meta:
        model = Pair
        fields = ('second',)

    def clean(self):
        first = None # how can I get first?
        second = self.cleaned_data.get("second")

        if (first == second):
            raise ValidationError("You can't pair with yourself, silly.")

def pair_create(request):
    if request.method == 'POST':
        pair = Pair()
        pair.first = request.user
        form = PairForm(instance=pair, data=request.POST)
        if form.is_valid():
            form.save();
            return HttpResponseRedirect(reverse('somewhere'))
    else:
        form = PairForm()

    return render_to_response('something.html', {
        'form': form,
    }, context_instance=RequestContext(request))
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登录用户想要与另一个用户配对.它们显示为带下拉列表的表单.如果他们自己选择,则提出验证错误.

问题:在PairForm的clean(self) …

django django-models django-forms

16
推荐指数
1
解决办法
2万
查看次数

Intellij IDEA X:要调整的任何多核设置?

我有一个很好的Mac Pro 4核+超线程.是否有任何Intellij设置需要调整才能利用这一点?通过GUI,还是编辑Info.plist文件?

我对使GWT编译/执行更快更感兴趣.(我已经 localWorkers 4设定好了).

谢谢

performance multicore intellij-idea

8
推荐指数
1
解决办法
3038
查看次数

关于编译时错误的问题

#!/usr/bin/env perl
use warnings;
use 5.012;

say "no semicolon"

say "World";
say "World";
say "World";
say "World";
say "World";

# syntax error at ./perl1.pl line 7, near "say"
# Execution of ./perl1.pl aborted due to compilation errors.
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.

#!/usr/bin/env perl
use warnings;
use 5.012;

my $character = "\x{ffff}";

say "Hello";
say "Hello";
say "Hello";
say "Hello";
say "Hello";

# Unicode non-character 0xffff is illegal for interchange at ./perl1.pl line 5.
# Hello
# Hello
# Hello
# Hello
# Hello …
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perl compilation

2
推荐指数
1
解决办法
308
查看次数

Capybara:如何测试页面的标题?

在使用Steak,Capybara和RSpec的Rails 3应用程序中,如何测试页面标题?

rspec ruby-on-rails capybara

68
推荐指数
3
解决办法
2万
查看次数

连接框架意味着什么?(IOS)

我不清楚框架的链接是什么以及如何做到这一点.这听起来只是连接框架的弱点,但我认为不是.任何帮助,将不胜感激.谢谢!

iphone frameworks hyperlink ipad ios

3
推荐指数
1
解决办法
960
查看次数

如何编码和解码jpeg文件?

我想用C#在Windows应用程序中编码和解码jpg文件.

我怎么能这样做?

c# encoding jpeg decoding winforms

2
推荐指数
1
解决办法
3517
查看次数

Android:无法为AsyncTask指定List <String>返回类型:doInBackground

我有以下基于asynctask的代码块.我试图通过返回LoadFeed()返回List变量,并且doInBackground的返回类型是String.如果我将doInBackground的返回类型从String更改为List,那么我会收到错误

"The return type is incompatible with AsyncTask<String,Void,String>.doInBackground(String[])"
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我该如何解决这个错误?请帮忙

谢谢,

  private class DispData extends AsyncTask<String, Void, String> {
   private final ProgressDialog dialog = new ProgressDialog(MessageList.this);
   // can use UI thread here
   protected void onPreExecute() {
      dialog.setMessage("Fetching scores...");
      dialog.show();
   }


   // automatically done on worker thread (separate from UI thread)
   protected String doInBackground(final String... args) {
      return loadFeed();

   }


  // can use UI thread here
   protected void onPostExecute(final List<String> result) {
      if (dialog.isShowing()) {
         dialog.dismiss();
      }
     adapter = 
            new ArrayAdapter<String>(MessageList.this,R.layout.row,result);
     MessageList.this.setListAdapter(adapter); …
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android list android-asynctask

3
推荐指数
1
解决办法
7331
查看次数