小编Raj*_*ana的帖子

ansible find:获取目录的路径

在 find 中我得到以下输出,如何仅过滤路径?

find:
  paths: /jv01
  recurse: yes
  file_type: directory
  patterns: 'agent_13.3.0.0.0'
register: oem
- debug:
  var: oem

"oem": {
        "changed": false,
        "examined": 24156,
        "failed": false,
        "files": [
            {
                "atime": 1545128921.5473044,
                "ctime": 1545120358.3347161,
                "dev": 64768,
                "gid": 1027,
                "inode": 67,
                "isblk": false,
                "ischr": false,
                "isdir": true,
                "isfifo": false,
                "isgid": false,
                "islnk": false,
                "isreg": false,
                "issock": false,
                "isuid": false,
                "mode": "0755",
                "mtime": 1545120358.3347161,
                "nlink": 28,
                "path": "/jv01/oracle/agent_13.3.0.0.0",
                "rgrp": true,
                "roth": true,
                "rusr": true,
                "size": 4096,
                "uid": 1027,
                "wgrp": false,
                "woth": false,
                "wusr": …
Run Code Online (Sandbox Code Playgroud)

ansible

2
推荐指数
1
解决办法
2万
查看次数

标签 统计

ansible ×1