小编Ala*_*Cor的帖子

我想创建一个函数，以便创建一个具有特定结构的表，将表名的一部分作为参数传递，因此表名是 t_ 。与此类似：

CREATE OR REPLACE FUNCTION create_table_type1(t_name VARCHAR(30)) RETURNS VOID AS $$
BEGIN
    EXECUTE "CREATE TABLE IF NOT EXISTS t_"|| t_name ||"
    (
    id SERIAL,
    customerid INT,
    daterecorded DATE,
            value DOUBLE PRECISION,
    PRIMARY KEY (id)
    )"
END
$$ LANGUAGE plpgsql

然后像这样调用它：

SELECT create_table_type1('one');

是否可以？

考虑下表

Device
--------
id
name
type
--------

components
--------
id INT
type VARCHAR
--------

Manufacturers
-------------
id INT
name VARCHAR
country VARCHAR
-------------

Device_components
-----------------
deviceid REFERENCES Devices(id)
componentid REFERENCES Components(id)
-----------------

Component_Manufacturers
-----------------------
componentid REFERENCES Components(id)
manufacturerid REFERENCES Manufacturers(id)
-----------------------

我想查询数据库以返回如下内容：

{
 "id": 1,
  "name": "phone",
  "components": [
    {
      "id": 1,
      "type": "screen",
      "manufacturers": [
       {
         "id": 1,
          "name": "a",
          "country": "Germany"
        }
      ]
   },
   {
     "id": 2,
      "type": "keyboard",
      "manufacturers": [
        {
         "id": 1,
          "name": "a",
          "country": "UK" …