如何将参数传递给函数

ale*_*smn 4 postgresql view functions

目前我创建了一个视图,请在答案中查看。如何根据该crosstab()查询创建函数,以便传递日期并获取特定日期的数据?

多次调用该函数并传递不同的日期来填充图表(例如)也是一种好习惯吗?

Erw*_*ter 12

我建议使用 SQL 函数:

CREATE OR REPLACE FUNCTION foo(_date date)
  RETURNS TABLE (
   name       text  -- types have to match your actual types!
 , keyword_id int
 , project_id int
 , the_date   date
 , today      int
 , yesterday  int
 , week       int
 , month      int) AS
$func$

SELECT k.name, f.keyword_id, f.project_id, _date -- AS the_date -- col alias irrelevant
     , f.t AS today, f.y As yesterday, f.w AS week, f.m AS month
FROM   crosstab(

    -- crosstab function from previous question here
    -- http://dba.stackexchange.com/a/71266/3684

   ) f (rn int, keyword_id int, project_id int
       , t int, y int, w int, m int)
JOIN   keyword k USING (keyword_id);

$func$  LANGUAGE sql;
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称呼:

SELECT * FROM foo('2014-07-07');
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now()::date名为 的输入参数替换所有出现的_date
在 Postgres 9.1 或更早版本中,$1在 SQL 函数中使用位置参数(可以在任何版本中使用)。

更多代码示例:

棘手的细节

crosstab()函数将查询字符串作为参数。函数参数在里面是不可见的crosstab()。所以你需要将日期值作为字符串文字传递!为方便起见,
我建议使用该功能format()。例如,第二个参数变为:

,format('VALUES(%L::date), (%L), (%L), (%L)'
        , $1, $1 - 1, $1 - 7, ($1 - interval '1 month')::date
       )
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代替:

,$$
 VALUES
       (now()::date)
     , (now()::date - 1)
     , (now()::date - 7)
     , ((now() - interval '1 month')::date)
 $$
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完整代码

SQL函数

CREATE OR REPLACE FUNCTION foo_sql(_date date)
  RETURNS TABLE (
   name       text
 , keyword_id int
 , project_id int
 , the_date   date
 , today      int
 , yesterday  int
 , week       int
 , month      int) AS
$func$
BEGIN

SELECT k.name, f.keyword_id, f.project_id, _date
     , f.t, f.y, f.w, f.m
FROM   crosstab (
   $$
   SELECT rn
        , pk.keyword_id
        , pk.project_id
        , d.created_at
        , COALESCE(pr.pos, 0)
   FROM  (SELECT *, row_number() OVER () AS rn FROM project_keyword) pk
   CROSS  JOIN (
       $$
    || format('VALUES(%L::date), (%L), (%L), (%L)'
              , $1, $1 - 1, $1 - 7, ($1 - interval '1 month')::date)
   || $$
     ) d(created_at)
   LEFT JOIN (
      SELECT keyword_id
           , project_id
           , created_at::date AS created_at
           , min(position) AS pos
      FROM   project_report
      GROUP  BY keyword_id, project_id, created_at::date
      ) pr USING (keyword_id, project_id, created_at)
   ORDER  BY pk.rn, d.created_at
   $$

  ,format('VALUES(%L::date), (%L), (%L), (%L)'
              , $1, $1 - 1, $1 - 7, ($1 - interval '1 month')::date)
   ) f (rn int, keyword_id int, project_id int
       , t int, y int, w int, m int)
JOIN   keyword k USING (keyword_id);

END
$func$  LANGUAGE sql;
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PL/pgSQL 函数

更短,重用VALUES表达式。也可能快一点。

CREATE OR REPLACE FUNCTION foo_plpgsql(_date date)
  RETURNS TABLE (name text, keyword_id int, project_id int, the_date date
               , today int, yesterday int, week int, month int) AS
$func$
DECLARE
   _dates text := format('VALUES(%L::date), (%L), (%L), (%L)'
                        , $1, $1 - 1, $1 - 7, ($1 - interval '1 month')::date);
BEGIN

SELECT k.name, f.keyword_id, f.project_id, _date, f.t, f.y, f.w, f.m
FROM   crosstab (
  'SELECT rn
        , pk.keyword_id
        , pk.project_id
        , d.created_at
        , COALESCE(pr.pos, 0)
   FROM  (SELECT *, row_number() OVER () AS rn FROM project_keyword) pk
   CROSS  JOIN (
       ' || _dates || '
     ) d(created_at)
   LEFT JOIN (
      SELECT keyword_id
           , project_id
           , created_at::date AS created_at
           , min(position) AS pos
      FROM   project_report
      GROUP  BY keyword_id, project_id, created_at::date
      ) pr USING (keyword_id, project_id, created_at)
   ORDER  BY pk.rn, d.created_at'

  ,_dates
   ) f (rn int, keyword_id int, project_id int, t int, y int, w int, m int)
JOIN   keyword k USING (keyword_id);

END
$func$  LANGUAGE plpgsql;
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CTE

为了完整起见,“相同”没有持久化函数,带有CTE

WITH d(day)   AS (SELECT '2014-07-07'::date)  -- provide your date here
,    v(dates) AS (
   SELECT format('VALUES(%L::date), (%L), (%L), (%L)'
                 , day, day - 1, day - 7
                 ,(day - interval '1 month')::date)
   FROM d
   )
SELECT k.name, f.keyword_id, f.project_id, d.day AS the_date
     , f.t AS today, f.y As yesterday, f.w AS week, f.m AS month
FROM   crosstab (
  'SELECT rn
        , pk.keyword_id
        , pk.project_id
        , d.created_at
        , COALESCE(pr.pos, 0) AS pos
   FROM  (SELECT *, row_number() OVER () AS rn FROM project_keyword) pk
   CROSS  JOIN (
       ' || (SELECT dates FROM v) || '
     ) d(created_at)
   LEFT JOIN (
      SELECT keyword_id
           , project_id
           , created_at::date AS created_at
           , min(position) AS pos
      FROM   project_report
      GROUP  BY keyword_id, project_id, created_at::date
      ) pr USING (keyword_id, project_id, created_at)
   ORDER  BY pk.rn, d.created_at'

  ,(SELECT dates FROM v)
   ) f (rn int, keyword_id int, project_id int
       , t int, y int, w int, m int)
JOIN   keyword k USING (keyword_id);
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