执行过程时无限循环

Question

我有这张表，有 3 条记录。3条记录是创建脚本。我需要执行创建脚本，如果发生208错误，那么我需要保留记录并将状态设置为1。然后在其他记录完成后再次执行它。如果没有错误或者有除 208 之外的任何其他错误，我需要从表中删除它。但是当我执行它时，它会无限循环。我该如何解决？

问题是第二个视图参考了第一个视图。所以我需要先创建第二个，然后创建第一个。这就是我创建这个 SP 的原因。任何其他想法也表示赞赏。我是编码新手，所以请原谅我犯的任何错误。

Create PROCEDURE [dbo].[UP_CREATE_SCRIPT]

AS 

BEGIN 

declare @qry1 nvarchar(max)
DECLARE @i INT =1
DECLARE @qry2 NVARCHAR(100) 
IF EXISTS (select 1 from [SmartMigrateDB_New].dbo.temp3 where id>0 and type<>'sq') 

BEGIN 
truncate  table error_log

    while (select count(1) from [SmartMigrateDB_New].dbo.temp3 where status=1)>=0

    BEGIN 
        WHILE @i <=  (SELECT MAX(ID) FROM [SmartMigrateDB_New].dbo.temp3)
           BEGIN
            BEGIN TRY
             set @qry1 = ( select code from [SmartMigrateDB_New].dbo.temp3  where id = @i  )
             print @qry1                        
             EXEC sp_ExecuteSQL @qry1
             update [SmartMigrateDB_New].dbo.temp3 set status=0  where id = @i
            END TRY


            BEGIN CATCH
             if ERROR_NUMBER()=208
             update [SmartMigrateDB_New].dbo.temp3 set status=1  where id = @i
             if ERROR_NUMBER()<>208
             update [SmartMigrateDB_New].dbo.temp3 set status=0   where id = @i

             insert into error_log(name,error_no,msg)
             SELECT 
             ERROR_PROCEDURE() as name,
             ERROR_NUMBER() AS error_no,
             ERROR_MESSAGE() AS msg
   
            END CATCH
            
            SET @qry2=(SELECT NAME FROM [SmartMigrateDB_New].dbo.temp3 where id = @i    )
            delete from [SmartMigrateDB_New].dbo.temp3 where id=@i and  status=0  
            print @qry2 +' Created'
            set @i = @i + 1 
           END
    END

END
ELSE print 'no objects'
END

Answer 1

当您循环使用非连续值的标识符时，您需要以不同的方式处理递增。这是一个简单的例子：

DECLARE
    @t table (id int PRIMARY KEY);

INSERT 
    @t
(
    id
)
SELECT 
    ABS(ao.object_id)
FROM sys.all_objects AS ao;

DECLARE
    @min bigint,
    @max bigint;

SELECT
    @min = MIN(t.id),
    @max = MAX(t.id)
FROM @t AS t;

WHILE @min < @max
BEGIN
    RAISERROR('Current value: %I64d', 0, 1, @min) WITH NOWAIT;
    
    SELECT TOP (1)
        @min = t.id
    FROM @t AS t
    WHERE t.id > @min
    ORDER BY t.id;
END;

这将找到大于当前标识符的下一个标识符，而不会增加到它们之间不存在的值。