hug*_*eow 3 mysql query mysql-console gaps-and-islands
如何找到[1, 161]结果集中没有的两个数字?
我可以使用 sql 命令找到这两个数字吗?
mysql> select blog_id from wp_blogs;
...
| 149 |
| 150 |
| 151 |
| 152 |
| 153 |
| 154 |
| 155 |
| 156 |
| 157 |
| 158 |
| 159 |
| 160 |
| 161 |
+---------+
159 rows in set (0.25 sec)
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序列是从1到161,应该有161个数字,但结果集中只有159个数字。
mysql> select count(blog_id) from wp_blogs;
+----------------+
| count(blog_id) |
+----------------+
| 159 |
+----------------+
1 row in set (0.24 sec)
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如何找到丢失的数字?
Phi*_*lᵀᴹ 11
要查找数字范围内的间隙:
测试表及数据:
mysql> CREATE TABLE wp_blogs
-> (
-> blog_id INTEGER
-> );
mysql> insert into wp_blogs values(1);
mysql> insert into wp_blogs values(2);
mysql> insert into wp_blogs values(4);
mysql> insert into wp_blogs values(6);
mysql> insert into wp_blogs values(7);
mysql> insert into wp_blogs values(8);
mysql> insert into wp_blogs values(10);
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询问:
mysql> SELECT a.blog_id+1 AS start, MIN(b.blog_id) - 1 AS end
-> FROM wp_blogs AS a, wp_blogs AS b
-> WHERE a.blog_id < b.blog_id
-> GROUP BY a.blog_id
-> HAVING start < MIN(b.blog_id);
+-------+------+
| start | end |
+-------+------+
| 3 | 3 |
| 5 | 5 |
| 9 | 9 |
+-------+------+
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