mou*_*r11 7 postgresql functions date interval
我想生成给定日期的通用季度结束日期。
例如:如果我有2010-01-01,我想返回2010-03-31,等等。
我可以得到季度号和年份:
select to_char(date_trunc('quarter', current_date)::date, 'yyyy-q');
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2017-3从今天起返回的是2017-07-14
我如何很好地获得季度结束日期?
我可以得到答案,但它非常丑陋:
select to_char(date_trunc('year', date '2015-01-01'),'yyyy') || '-' ||case
when (select extract('quarter' from date_trunc('quarter', date '2015-01-01')::date )) = 1 then '03-31'
when (select extract('quarter' from date_trunc('quarter', date '2015-01-01')::date )) = 2 then '06-30'
when (select extract('quarter' from date_trunc('quarter', date '2015-01-01')::date )) = 3 then '09-30'
when (select extract('quarter' from date_trunc('quarter', date '2015-01-01')::date )) = 4 then '12-31'
else '?'
end
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返回2015-03-31因为我把2015-01-01。
有没有更好的办法?
joa*_*olo 13
我认为解决这个问题的最短和最优雅的方法是使用date_trunc('quarter',d)(将检索季度的开始)+ 3 个月 - 1 天,并使用表达式创建一个FUNCTION:
CREATE FUNCTION end_of_quarter (d date)
RETURNS date AS
$$
SELECT
CAST(date_trunc('quarter', d) + interval '3 months' - interval '1 day' AS date)
$$
LANGUAGE SQL IMMUTABLE ;
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...然后使用它:
SELECT
d, end_of_quarter(d)
FROM
(SELECT
CAST(d0 AS date) AS d
FROM
generate_series(date '2017-01-01', date '2017-12-31', interval '6 days') AS s(d0)
) AS q ;
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d | 季末 :---------- | :------------- 2017-01-01 | 2017-03-31 ... 2017-03-26 | 2017-03-31 2017-04-01 | 2017-06-30 ... 2017-06-18 | 2017-06-30 2017-07-06 | 2017-09-30 2017-07-12 | 2017-09-30 ... 2017-09-22 | 2017-09-30 2017-09-28 | 2017-09-30 2017-10-04 | 2017-12-31 2017-10-10 | 2017-12-31 ... 2017-12-21 | 2017-12-31 2017-12-27 | 2017-12-31
您还可以通过使用以下简单版本来缩短您的原始方法CASE expression WHEN value THEN ...:
SELECT
d,
extract('year' from d) || '-' ||
/* case expression when value instead of case when expression */
case extract('quarter' from d)
when 1 then '03-31'
when 2 then '06-30'
when 3 then '09-30'
else '12-31'
end AS end_of_quarter
FROM
generate_series(date '2017-01-01', date '2017-12-31', interval '6 days') AS s(d) ;
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如果您需要经常这样做,请定义一个函数:
CREATE FUNCTION end_of_quarter (d date)
RETURNS date AS
$$
SELECT
cast (extract('year' from d) || '-' ||
case extract('quarter' from d)
when 1 then '03-31'
when 2 then '06-30'
when 3 then '09-30'
else '12-31'
end
AS date)
$$
LANGUAGE SQL IMMUTABLE ;
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dbfiddle在这里