使用 sed 删除多个空格

Question

我有一句话：

171211 22043707      21641 xxxx     xxxxxxx  From (,,xxxx,xxxx) Vxxxx1:  xxxxxx
171212 13441585        417 xxxx     xxxxxxxx Server manager informed of process termination, pinfo =  x,0000032585 13:44:15

171211 22043707问题是和之间的空间21641有所不同。我想将其替换为一个空格。我该怎么做呢？哪条sed命令可以匹配一个或多个空格？

Answer 1

有了tr你，你可以更轻松地做到这一点：

tr -s ' '

来自tr男人：

 -s, --squeeze-repeats
          replace each input sequence of a repeated character that is
          listed in SET1 with a single occurrence of that character