在Python中将.txt文件转换为图像

Question

我有一些代码可以将图像转换为ascii艺术图像。当前，它将其输出为.txt文件，但该文件可以包含数十万个字符。如何将文件转换为图像，例如.png文件？

当前，它基于像素密度构建字符向量，然后将向量写入.txt图像。

Answer 1

如果我理解正确，您想要的图像看起来就像是有人在拍摄的ascii艺术的屏幕截图一样，就像在巨大的无限制文本编辑器中看到的一样。

我做了一些类似的事情，用PILLOW以编程方式生成文本。这里是由改性的例子此矿井的代码。希望这段代码可以帮助您和其他人避免为弄清楚如何使事情看起来合理而不得不做的事情。

这是从下面的代码获得的示例结果。

该代码是对链接库的直接修改，可以使用文本文件而不是字符串。

import PIL
import PIL.Image
import PIL.ImageFont
import PIL.ImageOps
import PIL.ImageDraw

PIXEL_ON = 0  # PIL color to use for "on"
PIXEL_OFF = 255  # PIL color to use for "off"


def main():
    image = text_image('content.txt')
    image.show()
    image.save('content.png')


def text_image(text_path, font_path=None):
    """Convert text file to a grayscale image with black characters on a white background.

    arguments:
    text_path - the content of this file will be converted to an image
    font_path - path to a font file (for example impact.ttf)
    """
    grayscale = 'L'
    # parse the file into lines
    with open(text_path) as text_file:  # can throw FileNotFoundError
        lines = tuple(l.rstrip() for l in text_file.readlines())

    # choose a font (you can see more detail in my library on github)
    large_font = 20  # get better resolution with larger size
    font_path = font_path or 'cour.ttf'  # Courier New. works in windows. linux may need more explicit path
    try:
        font = PIL.ImageFont.truetype(font_path, size=large_font)
    except IOError:
        font = PIL.ImageFont.load_default()
        print('Could not use chosen font. Using default.')

    # make the background image based on the combination of font and lines
    pt2px = lambda pt: int(round(pt * 96.0 / 72))  # convert points to pixels
    max_width_line = max(lines, key=lambda s: font.getsize(s)[0])
    # max height is adjusted down because it's too large visually for spacing
    test_string = 'ABCDEFGHIJKLMNOPQRSTUVWXYZ'
    max_height = pt2px(font.getsize(test_string)[1])
    max_width = pt2px(font.getsize(max_width_line)[0])
    height = max_height * len(lines)  # perfect or a little oversized
    width = int(round(max_width + 40))  # a little oversized
    image = PIL.Image.new(grayscale, (width, height), color=PIXEL_OFF)
    draw = PIL.ImageDraw.Draw(image)

    # draw each line of text
    vertical_position = 5
    horizontal_position = 5
    line_spacing = int(round(max_height * 0.8))  # reduced spacing seems better
    for line in lines:
        draw.text((horizontal_position, vertical_position),
                  line, fill=PIXEL_ON, font=font)
        vertical_position += line_spacing
    # crop the text
    c_box = PIL.ImageOps.invert(image).getbbox()
    image = image.crop(c_box)
    return image


if __name__ == '__main__':
    main()

顺便说一句，所有这些代码可能都不应该填充在一个函数中，但是我认为对于示例代码而言，它变得更加简单。

Answer 2

看看Pillow（这里有文档）

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从上面的链接文档：

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这里\xe2\x80\x99s是一个简单的例子：

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import ImageFont, ImageDraw\n\ndraw = ImageDraw.Draw(image)\n\n# use a bitmap font\nfont = ImageFont.load("arial.pil")\n\ndraw.text((10, 10), "hello", font=font)\n\n# use a truetype font\nfont = ImageFont.truetype("arial.ttf", 15)\n\ndraw.text((10, 25), "world", font=font)\n

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