我正在尝试从 person.csv（如下）中删除行，条件是该人不是在过去 1 年出生的：
数据集1：
"Index","User Id","First Name","Last Name","Date of birth","Job Title"
"1","9E39Bfc4fdcc44e","new, Diamond","Dudley","06 Dec 1945","Photographer"
"3","32C079F2Bad7e6F","Ethan","Hanson","08 Mar 2014","Actuary"
"2","aaaaaaa, bbbbbb","Grace","Huerta","21 Jan 2023","Visual merchandiser"
因此，预期的输出如下所示（最后一行在不到一年的时间内被删除）：
"Index","User Id","First Name","Last Name","Date of birth","Job Title"
"1","9E39Bfc4fdcc44e","new, Diamond","Dudley","06 Dec 1945","Photographer"
"3","32C079F2Bad7e6F","Ethan","Hanson","08 Mar 2014","Actuary"
我尝试使用 awk 来执行以下操作：
awk -F , '{print $5 ....}' person.csv > output.csv
但是，无法弄清楚如何将每行日期与（今天减去 1 年）进行比较。
Dataset2：有时双引号字段内可能有双引号，例如（line1 field4）：
"Index","User Id","First Name","Last Name","Date of birth","Job Title"
"1","9E39Bfc4fdcc44e","new, Diamond","Dudley (aka "dud")","03 Oct 2023","Photographer"
"3","32C079F2Bad7e6F","Ethan","Hanson","03 Dec 2022","Actuary"
"2","aaaaaaa, bbbbbb","Grace","Huerta","21 Jan 2023","Visual merchandiser"
如果“sed”可以做到这一点，我也持开放态度。请任何帮助，谢谢！