小编asa*_*adz的帖子

我想重用这里给出的代码，但我一直在理解使用sed：

print "Sending to QRadar...\n";
# SSH To QRadar's Console and push out file + trigger update
`scp -i $qradar_ssh_key -o UserKnownHostsFile=$qradar_ssh_knownhosts -o StrictHostKeyChecking=no root\@$qradar_console:/store/configservices/staging/globalconfig/remotenet.conf .`;
`sed -i -e '/^SECULERT/d' remotenet.conf`;
`cat $seculert_qradar_list >> remotenet.conf`;
`scp -i $qradar_ssh_key -o UserKnownHostsFile=$qradar_ssh_knownhosts -o StrictHostKeyChecking=no remotenet.conf root\@$qradar_console:/store/configservices/staging/globalconfig/remotenet.conf`;

我想知道sed这里在做什么。

我的文件内容为：

this line 1 no un1x
this lines 22 0
butbutbut this 33 22 has unix
but not 1
THIS is not
butbutbut ffff
second line

awk 'NR==2 && NR==3 {f=$0;next}  NR ==5 &&f{print;print f}' awk.write

这里的问题是，f我只能保存nr==3我想在第 5 行之后移动第 2 行和第 3 行的值。