为什么下面不打印 3 2 1 6 5 4?
echo '1 2 3 4 5 6' | while read a b c; do echo result: $c b a; done
前三个数字不是按顺序读取,反向打印,然后读取最后三个数字并反向吗?
bash shell-script text-processing read
bash ×1
read ×1
shell-script ×1
text-processing ×1