MLS*_*LSC 5 partition mount fstab rename
我/part
在我的机器上做了一个分区,里面有一些重要的数据......
但我受不了它的名字......
我想要一个明确的解决方案来解决它并将其名称更改为例如/test
...
如您所见,这是我的/etc/fstab
信息:
# /etc/fstab: static file system information.
#
# Use 'blkid' to print the universally unique identifier for a
# device; this may be used with UUID= as a more robust way to name devices
# that works even if disks are added and removed. See fstab(5).
#
# <file system> <mount point> <type> <options> <dump> <pass>
proc /proc proc nodev,noexec,nosuid 0 0
# / was on /dev/sda5 during installation
UUID=a21a99c4-e5b4-4197-ac5e-80d0fab1f30c / ext4 errors=remount-ro 0 1
# /home was on /dev/sda6 during installation
UUID=2e37d833-ca34-4fa7-a5d8-a4423a5af9bc /home ext4 defaults 0 2
# /part was on /dev/sda7 during installation
UUID=47e6e0b1-0e57-4184-a378-375b9ce315c5 /part ext4 defaults 0 2
# swap was on /dev/sda1 during installation
UUID=485e9f78-4dce-4404-af4e-f43985525264 none swap sw 0 0
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重点是:我的信息很重要,我害怕在不确定的情况下操纵它......我想要一个安全的解决方案......
这怎么可能?
卸载分区:
# umount /part
Run Code Online (Sandbox Code Playgroud)确保未挂载后重命名目录:
# mountpoint /part &>/dev/null || mv /part /best_name_ever
Run Code Online (Sandbox Code Playgroud)编辑/etc/fstab
替换/part
为/best_name_ever
重新挂载分区:
mount /best_name_ever
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当然是为了代表您的root
提示,而不是要输入的实际输入。
在虚拟数据上测试此解决方案或任何其他解决方案的安全性
以下说明(部分)从虚拟文件系统中窃取:从普通文件构建 Linux 文件系统。
创建一个大小为 20 MB 的普通文件(例如):
$ dd if=/dev/zero of=dummy_fs bs=1k count=20480 # 20480 = 20 * 1024
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在您的文件上创建一个文件系统:
$ /sbin/mkfs -t ext4 dummy_fs
mke2fs 1.42.5 (29-Jul-2012)
dummy_fs is not a block special device.
Proceed anyway? (y,n) y
... # Output of mkfs
Run Code Online (Sandbox Code Playgroud)挂载文件系统映像,在其上创建一些虚拟数据并测试解决方案:
# mkdir /tmp/testmount
# mount -o loop dummy_fs /tmp/testmount
# touch /tmp/testmount/{blah,bleh} # Create dummy data
# ls /tmp/testmount
blah bleh lost+found
# umount /tmp/testmount
# mountpoint /tmp/testmount &>/dev/null || mv /tmp/testmount /tmp/sexy_name
# mount -o loop dummy_fs /tmp/sexy_name
# ls /tmp/sexy_name # to ensure your data is intact:
blah bleh lost+found
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