我从看起来像这样的 json 开始:
{
"object": "list",
"data": [
{
"id": "in_1HW85aFGUwFHXzvl8wJbW7V7",
"object": "invoice",
"account_country": "US",
"customer_name": "clientOne",
"date": 1601244686,
"livemode": true,
"metadata": {},
"paid": true,
"status": "paid",
"total": 49500
},
{
"id": "in_1HJlIZFGUwFHXzvlWqhegRkf",
"object": "invoice",
"account_country": "US",
"customer_name": "clientTwo",
"date": 1598297143,
"livemode": true,
"metadata": {},
"paid": true,
"status": "paid",
"total": 51000
},
{
"id": "in_1HJkg5FGUwFHXzvlYp2uC63C",
"object": "invoice",
"account_country": "US",
"customer_name": "clientThree",
"date": 1598294757,
"livemode": true,
"metadata": {},
"paid": true,
"status": "paid",
"total": 57000
},
{
"id": "in_1H8B0pFGUwFHXzvlU6nrOm6I",
"object": "invoice",
"account_country": "US",
"customer_name": "clientThree",
"date": 1595536051,
"livemode": true,
"metadata": {},
"paid": true,
"status": "paid",
"total": 20000
}
],
"has_more": true,
"url": "/v1/invoices"
}
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如果我做
cat sample.json | jq -C '.data[] | {invoice_id: .id, date: .date | strftime("%Y-%m-%d"), amount: .total} | .amount = "$" + (.amount/100|tostring)'
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我可以成功地整理它(实际数据要冗长得多,要消除数百行),所以这给了我:
{
"invoice_id": "in_1HW85aFGUwFHXzvl8wJbW7V7",
"date": "2020-09-27",
"amount": "$495"
}
{
"invoice_id": "in_1HJlIZFGUwFHXzvlWqhegRkf",
"date": "2020-08-24",
"amount": "$510"
}
{
"invoice_id": "in_1HJkg5FGUwFHXzvlYp2uC63C",
"date": "2020-08-24",
"amount": "$570"
}
{
"invoice_id": "in_1H8B0pFGUwFHXzvlU6nrOm6I",
"date": "2020-07-23",
"amount": "$200"
}
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但这是错误的顺序。我想按日期字段排序,以便最近的项目最后显示在底部。
我已经尝试了所有可以想象的错误。我sort_by(.date)
该如何申请?我不断收到cannot index string with string "date"
错误(以及其他各种错误,但主要是那个错误)。
tha*_*isp 10
从 man jq
sort, sort_by(path_expression) sort 函数对它的输入进行排序,它必须是一个数组。
一般来说,调用单独的jq
命令时,您必须使用-s
,--slurp
这将使这些顺序对象成为一个数组,然后您可以按键对其进行排序。
... | jq -s 'sort_by(.date)'
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现在,如果您已经有一个选择并且您希望该结果是一个数组,那么我想用括号将其全部包装起来就可以了:
jq '[ <some_existing_selection> ] | sort_by(.date)' file.json
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例子
对于您开始使用的 json,假设最初您正在做这样的事情(生成一系列对象):
jq '.data[] | {id: .id, date: .date}' file.json
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您必须将整个 jq 选择括在括号中以使其成为数组:
jq '[.data[] | {id: .id, date: .date}]' file.json
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现在可以对这个数组进行排序:
jq '[.data[] | {id: .id, date: .date}] | sort_by(.date)' file.json
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