使用 Bash / awk 在 csv 文件的第一列中填充空格

Question

我正在研究自动化一些流程/计算，但我可能首先需要格式化一个有点尴尬的CSV文件集。（为此，我bash根据要求使用了 ）。

csv 文件集遵循（大致）以下格式

CODE,Sitting,Jan,Feb,Mar,Apr,May,Jun,Jul,Totals
CLLK_J9,First Sitting,,,2,5,2,,,10
,Second Sitting,,,,,,,,1
RTHM_A8,First Sitting,,,1,,3,,,6
,Second Sitting,,,,,1,,,1
FFBJ_FA9,First Sitting,,,,8,6,,,25
,Second Sitting,,,,,11,,,12
UUYIOR_HJ9,First Sitting,,,1,3,6,,,17
IKRO_Lk8,First Sitting,,,,3,3,,,37
,Second Sitting,,,,6,11,,,34

我试图CODE用上一行的字段内容填充列中的空字段（通常这些空字段出现在第 2 列中的“第二次坐”实例旁边）。所以，对于上面的例子，结果应该是

CODE,Sitting,Jan,Feb,Mar,Apr,May,Jun,Jul,Totals
CLLK_J9,First Sitting,,,2,5,2,,,10
CLLK_J9,Second Sitting,,,,,,,,1
etc.

我开始阅读一些awk文档，因为它似乎是完成这项任务的相当强大的实用程序 - 但还没有取得任何进展。想法？

塔

Answer 1

使用 Miller ( https://github.com/johnkerl/miller ) 非常简单。跑步

mlr --csv fill-down -f CODE input.csv >output.csv

你将会有

+------------+----------------+-----+-----+-----+-----+-----+-----+-----+--------+
| CODE       | Sitting        | Jan | Feb | Mar | Apr | May | Jun | Jul | Totals |
+------------+----------------+-----+-----+-----+-----+-----+-----+-----+--------+
| CLLK_J9    | First Sitting  | -   | -   | 2   | 5   | 2   | -   | -   | 10     |
| CLLK_J9    | Second Sitting | -   | -   | -   | -   | -   | -   | -   | 1      |
| RTHM_A8    | First Sitting  | -   | -   | 1   | -   | 3   | -   | -   | 6      |
| RTHM_A8    | Second Sitting | -   | -   | -   | -   | 1   | -   | -   | 1      |
| FFBJ_FA9   | First Sitting  | -   | -   | -   | 8   | 6   | -   | -   | 25     |
| FFBJ_FA9   | Second Sitting | -   | -   | -   | -   | 11  | -   | -   | 12     |
| UUYIOR_HJ9 | First Sitting  | -   | -   | 1   | 3   | 6   | -   | -   | 17     |
| IKRO_Lk8   | First Sitting  | -   | -   | -   | 3   | 3   | -   | -   | 37     |
| IKRO_Lk8   | Second Sitting | -   | -   | -   | 6   | 11  | -   | -   | 34     |
+------------+----------------+-----+-----+-----+-----+-----+-----+-----+--------+