递归替换目录中文件中的路径,二进制文件除外

min*_*nto 0 linux command-line sed find path

如何递归替换目录中文件中的字符串(位置路径),二进制文件除外?我试过命令

find . -type f -exec sed -i 's/foo/bar/g' {} +
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但它也会替换二进制文件和其他文件(*.o、*.c)中的字符串。我想递归替换所有名为“.depend”的文件中的字符串。

ebv*_*vjr 5

find . -type f -name "*.depend" -exec sed -i 's/foo/bar/g' {} +

或者

find . -type f -not -name "*.c" -not -name "*.o" -exec sed -i 's/foo/bar/g' {} +

       -name pattern
              Base of file name (the path with the leading directories
              removed) matches shell pattern pattern.  Because the leading
              directories are removed, the file names considered for a match
              with -name will never include a slash, so `-name a/b' will
              never match anything (you probably need to use -path instead).
              A warning is issued if you try to do this, unless the
              environment variable POSIXLY_CORRECT is set.  The
              metacharacters (`*', `?', and `[]') match a `.' at the start
              of the base name (this is a change in findutils-4.2.2; see
              section STANDARDS CONFORMANCE below).  To ignore a directory
              and the files under it, use -prune; see an example in the
              description of -path.  Braces are not recognised as being
              special, despite the fact that some shells including Bash
              imbue braces with a special meaning in shell patterns.  The
              filename matching is performed with the use of the fnmatch(3)
              library function.  Don't forget to enclose the pattern in
              quotes in order to protect it from expansion by the shell.
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http://man7.org/linux/man-pages/man1/find.1.html