忽略awk中的第一条记录

Question

BEGIN{FS=","; t1 = 0; n = 0;  avg = 0; sum=0;  printf("%-10s %9s\n%-10s %9s","Name", "Average", "----", "-------") }

{
    if ($3 > 0){
        t1 += $3;
        n++;
    }
    sum = 0;
    if($3 > 0 && $4 > 0 && $5 >0){
        sum = $3 + $4 + $5;
        avg = sum / 3;
    }
    else if($3 < 0 && $4 > 0 && $5 >0){
            sum = $4 + $5;
        avg = sum / 2;
    }
    else if($3 > 0 && $4 < 0 && $5 >0){
        sum = $3 + $5;
        avg = sum / 2;
    }
    else if($3 < 0 && $4 > 0 && $5 < 0){
        sum = $3 + $4;
        avg = sum / 2;
    }

    printf("\n%-10s %7.2f", $1, avg);
}
END{
    printf("-------------------\nAverage for Test ! : %f.2", (t1/n));

    }

body part 命令应该忽略第一条记录。

Answer 1

您可以通过将记录号上的测试添加到您的块中来做到这一点：

NR > 1 {
    if ($3 > 0){
        t1 += $3;
        n++;
    }
    ...