如何匹配第 2 列 csv 文件并使用新数据更新列并将其保存到新文件

Question

我有ListIPv6.csv

2001:c00::-2001:dff:ffff:ffff:ffff:ffff:ffff:ffff,iana,1020211200,ZZ,,
2001:e00::-2001:fff:ffff:ffff:ffff:ffff:ffff:ffff,iana,1041379200,ZZ,,
2001:1200::-2001:13ff:ffff:ffff:ffff:ffff:ffff:ffff,iana,1036108800,ZZ,,
2001:1200::-2001:1200:ffff:ffff:ffff:ffff:ffff:ffff,lacnic,1042156800,MX,,
2001:1208::-2001:1208:ffff:ffff:ffff:ffff:ffff:ffff,lacnic,1044230400,MX,,
2001:1210::-2001:1210:ffff:ffff:ffff:ffff:ffff:ffff,lacnic,1095984000,MX,,
2001:1218::-2001:1218:ffff:ffff:ffff:ffff:ffff:ffff,lacnic,1120003200,MX,,

和CountryCode.csv

MX, MEXICO
NZ, NEWZOMBIE

当 ListIPv6.csv 的第 4 列与 CountryCode.csv 的第 1 列匹配时，我想从 CountryCode.csv 的第 2 列更新第 6 列 ListIPv6.csv

更新后的 ListIPv6.csv 的预期输出将是：

2001:c00::-2001:dff:ffff:ffff:ffff:ffff:ffff:ffff,iana,1020211200,ZZ,,
2001:e00::-2001:fff:ffff:ffff:ffff:ffff:ffff:ffff,iana,1041379200,ZZ,,
2001:1200::-2001:13ff:ffff:ffff:ffff:ffff:ffff:ffff,iana,1036108800,ZZ,,
2001:1200::-2001:1200:ffff:ffff:ffff:ffff:ffff:ffff,lacnic,1042156800,MX,,MEXICO
2001:1208::-2001:1208:ffff:ffff:ffff:ffff:ffff:ffff,lacnic,1044230400,MX,,MEXICO
2001:1210::-2001:1210:ffff:ffff:ffff:ffff:ffff:ffff,lacnic,1095984000,MX,,MEXICO
2001:1218::-2001:1218:ffff:ffff:ffff:ffff:ffff:ffff,lacnic,1120003200,MX,,MEXICO

我使用了下面的命令，但它没有满足我的标准。

sed -f <(printf 's/%s/%s/g\n' $(<CountryCode.csv)) <(head -n 1000 ListIPv6.csv) >NewListIPv6.csv

Answer 1

使用awk：

awk -F', *' 'NR==FNR{a[$1]=$2;next}{print $0 a[$4]}' CountryCode.csv ListIPv6.csv

该数组a用文件的行填充，CountryCode.csv然后另一个文件与数组的条目一起显示。