我想按公司名称的字母顺序对这个列表进行排序

Ras*_*had -3 ubuntu sort

所以我有一个名为的文件test.txt,其中包含以下几行。

 1.The Home Depot (Ranked 28): home improvement; Atlanta, GA.
 2.United Parcel Service (Ranked 48): shipping; Atlanta, GA.
 3.The Coca-Cola Company (Ranked 62): soft drinks; Atlanta, GA. 
 4.Delta Air Lines, Inc. (Ranked 68): airline; Atlanta, GA.
 5.Aflac, Incorporated (Ranked 135): insurance; Columbus, GA. 
 6.The Southern Company (Ranked 162): energy; Atlanta, GA.
 7.Genuine Parts Company (Ranked 183): replacement parts; Atlanta, GA. 
 8.First Data Corporation (Ranked 249): payment processing;Atlanta,GA. 
 9.WestRock (Ranked 251): corrugated and consumer Norcross, GA
10.HD Supply Holdings, Inc. (Ranked 320): industrial , Atlanta GA  
11.Suntrust Banks, Inc. (Ranked 329): banking; Atlanta, GA.
12.Mohawk Industries, Inc. (Ranked 338): flooring manufacturer; Calhoun, GA.
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我使用的命令是sed 's/[0-9]*[.]//' test.txt | awk -F"(" '{print NF,$1}' | sort仅按字母顺序给出公司名称。

Aflac, Incorporated
Delta Air Lines
Genuine Parts Company 
First Data Corporation
HD Supply Holdings
Mohawk Industries
Suntrust Banks
The Coca-Cola Company
The Home Depot
The Southern Company
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但是,我希望也显示整行,而不仅仅是公司名称。

ilk*_*chu 5

(取2)假设文件内容是:

  1.The Home Depot (Ranked 28): home improvement; Atlanta, GA.
  2.United Parcel Service (Ranked 48): shipping; Atlanta, GA.
  3.The Coca-Cola Company (Ranked 62): soft drinks; Atlanta, GA. 
  4.Delta Air Lines, Inc. (Ranked 68): airline; Atlanta, GA.
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由于您要排序的数据出现在一个点之后,您可以明确地将点设置为分隔符,-t .然后对第二个字段进行排序:

$ sort -t. -k2 test.txt
  4.Delta Air Lines, Inc. (Ranked 68): airline; Atlanta, GA.
  3.The Coca-Cola Company (Ranked 62): soft drinks; Atlanta, GA. 
  1.The Home Depot (Ranked 28): home improvement; Atlanta, GA.
  2.United Parcel Service (Ranked 48): shipping; Atlanta, GA.
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(问题中显示了一些前导空格。我只是在这里准确地复制了它,但它是否真的存在与排序无关。)

  • 确实如此。我讨厌这种重要的事情没有解释就改变了 (2认同)