将插入转换为选择

Question

我有一个具有以下格式的文件

INSERT INTO table1(field1,field2,field3) VALUES('values1','value2','value3');
INSERT INTO table1(field1,field2,field3) VALUES('other_values1','other_value2','other_value3');
INSERT INTO table1(field1,field2,field3) VALUES('another_values1','another_value2','another_value3');
INSERT INTO table2(table2_field1,table2_field2,table2_field3,field4) VALUES('table2_values1','table2_value2','table2_value3');
INSERT INTO table2(table2_field1,table2_field2,table2_field3,table2_field4) VALUES('other_table2_values1','other_table2_value2','other_table2_value3');
INSERT INTO table2(table2_field1,table2_field2,table2_field3,table2_field4) VALUES('another_table2_values1','another_table2_value2','another_table2_value3','another_table2_value4');

我想要这个输出

SELECT * FROM table1 WHERE field1='values1' AND field2='values2' AND field3=='values3';
SELECT * FROM table1 WHERE field1='other_values1' AND field2='other_values2' AND field3=='other_values3';
SELECT * FROM table1 WHERE field1='another_values1' AND field2='another_values2' AND field3=='another_values3';
SELECT * FROM table2 WHERE table2_field1='table2_values1' AND table2_field2='table2_values2' AND table2_field3=='table2_values3' AND table2_field4=='table2_values4';
SELECT * FROM table2 WHERE table2_field1='table2_values1' AND table2_field2='table2_values2' AND table2_field3=='table2_values3' AND table2_field4=='table2_values4';
SELECT * FROM table2 WHERE table2_field1='table2_values1' AND table2_field2='table2_values2' AND table2_field3=='table2_values3' AND table2_field4=='table2_values4';

到目前为止我所做的是

cat test_inserts |awk -F '[()]' '{print $1 " WHERE "$2 $4}' |sed 's/INSERT INTO /SELECT * FROM /g'

它给了我以下输出

SELECT * FROM table1 WHERE field1,field2,field3'values1','value2','value3'
SELECT * FROM table1 WHERE field1,field2,field3'other_values1','other_value2','other_value3'
SELECT * FROM table1 WHERE field1,field2,field3'another_values1','another_value2','another_value3'
SELECT * FROM table2 WHERE table2_field1,table2_field2,table2_field3,field4'table2_values1','table2_value2','table2_value3'
SELECT * FROM table2 WHERE table2_field1,table2_field2,table2_field3,table2_field4'other_table2_values1','other_table2_value2','other_table2_value3'
SELECT * FROM table2 WHERE table2_field1,table2_field2,table2_field3,table2_field4'another_table2_values1','another_table2_value2','another_table2_value3','another_table2_value4'

Answer 1

复杂的AWK解决方案：

awk -F'[()]' '{ sub(/INSERT INTO */,"",$1); 
                printf "SELECT * FROM %s WHERE ",$1;
                len=split($2, f, ","); split($4, v, ","); 
                for (i=1; i<=len; i++) printf "%s=%s%s", f[i], v[i], (i==len? ";":" AND ");
                print "" 
              }' test_inserts

• -F'[()]' - 复杂的字段分隔符
• sub(/INSERT INTO */,"",$1)-INSERT INTO从第一个字段中删除短语（提取表名）
• printf "SELECT * FROM %s WHERE ",$1- 打印包含表名的 SQL 语句的开头
• split($2, f, ",")- 通过分隔符拆分第二个字段,以获得字段名称（f成为字段名称数组）
• split($4, v, ",")- 通过分隔符分割第 4 个字段,以获得字段值（v成为字段值的数组）

输出：

SELECT * FROM table1 WHERE field1='values1' AND field2='value2' AND field3='value3';
SELECT * FROM table1 WHERE field1='other_values1' AND field2='other_value2' AND field3='other_value3';
SELECT * FROM table1 WHERE field1='another_values1' AND field2='another_value2' AND field3='another_value3';
SELECT * FROM table2 WHERE table2_field1='table2_values1' AND table2_field2='table2_value2' AND table2_field3='table2_value3' AND field4=;
SELECT * FROM table2 WHERE table2_field1='other_table2_values1' AND table2_field2='other_table2_value2' AND table2_field3='other_table2_value3' AND table2_field4=;
SELECT * FROM table2 WHERE table2_field1='another_table2_values1' AND table2_field2='another_table2_value2' AND table2_field3='another_table2_value3' AND table2_field4='another_table2_value4';