如果下一行包含则打印

Question

我有一个文本文件，需要从中找到 0 个发现蛋白质。我正在使用 Linux suse。任何使用 awk 或 sed 的命令将不胜感激

# BLASTP 2.2.31+
# Query: ABO10498.2 DNA replication initiator protein [Acinetobacter baumannii ATCC 17978]
# Database: uniprot-reviewed%3Ayes+AND+proteome%3Aup000005640.fasta
# Fields: query id, subject id, evalue, % identity, % query coverage per subject
# 1 hits found
# BLASTP 2.2.31+
# Query: ABO10538.2 hypothetical protein A1S_0043 [Acinetobacter baumannii ATCC 17978]
# Database: uniprot-reviewed%3Ayes+AND+proteome%3Aup000005640.fasta
# 0 hits found
# Query: ABO10591.2 putative acetyl-coA synthetase/AMP-(fatty) acid ligase [Acinetobacter baumannii ATCC 17978]
# Database: uniprot-reviewed%3Ayes+AND+proteome%3Aup000005640.fasta
# Fields: query id, subject id, evalue, % identity, % query coverage per subject
# 23 hits found
# BLASTP 2.2.31+
# Query: ABO10598.2 eR transcriptional regulator [Acinetobacter baumannii ATCC 17978]
# Database: uniprot-reviewed%3Ayes+AND+proteome%3Aup000005640.fasta
# 0 hits found

所需的输出：

# BLASTP 2.2.31+
# Query: ABO10538.2 hypothetical protein A1S_0043 [Acinetobacter baumannii ATCC 17978]
# Database: uniprot-reviewed%3Ayes+AND+proteome%3Aup000005640.fasta
# 0 hits found
# BLASTP 2.2.31+
# Query: ABO10598.2 eR transcriptional regulator [Acinetobacter baumannii ATCC 17978]
# Database: uniprot-reviewed%3Ayes+AND+proteome%3Aup000005640.fasta
# 0 hits found

Answer 1

如果模式保持不变，您可以使用

grep -B 3 '# 0 hits found'

这将打印包含# 0 hits found匹配前三行的所有行。

不同的命中由连续的线分开--。所以你可能想添加| grep -v '^--'到命令中。