如何删除第一列为空的行?

Lan*_*nes 3 sed awk text-processing

输入:

CC2352345|m,safnlasndfmnyxdcvyxcvyxcv             |klasjdf |3|lasdjflasdf|                    |2345567356
CC3543353|asdfasdffghntz                          |klasjdf |3|lsajdfl |                       |3456561235
CC5634554|asfjmklasdfassasdasasdsdfas             |klasjdf |3|lsajdfl |                       |2345635636
     |masdfjklasdfjasldfjlasjdfklas|          | |       |                       |2345234566
CC4723456|asdjkfasjkldfjaklsjdflkajldkfjlasjdflk  |klasjdf |2|lsajdfl |                       |2345234525
DD3455463|asldfklklfaem,.rtklqerktljekltjklqe     |klasjdf |3|lsajdfl |                       |4565467546
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输出:

CC2352345|m,safnlasndfmnyxdcvyxcvyxcv             |klasjdf |3|lasdjflasdf|                    |2345567356
CC3543353|asdfasdffghntz                          |klasjdf |3|lsajdfl |                       |3456561235
CC5634554|asfjmklasdfassasdasasdsdfas             |klasjdf |3|lsajdfl |                       |2345635636
CC4723456|asdjkfasjkldfjaklsjdflkajldkfjlasjdflk  |klasjdf |2|lsajdfl |                       |2345234525
DD3455463|asldfklklfaem,.rtklqerktljekltjklqe     |klasjdf |3|lsajdfl |                       |4565467546
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问题:如何删除第一列为空的行?

rus*_*ush 5

用这个:

sed '/^\s\s*/d' file
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甚至:

grep -v '^\s' file
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