Grepping strace 输出变得困难

Question

我编写了以下代码来确定程序写入哪些文件。我当然想捕获文件名。

strace -f -t -e trace=file -p 8804 2>&1 | grep -oP "\"(.*)\".*O_WRONLY"

这输出类似

/tmp/11111111.txt", O_WRONLY

问题是我无法将所有这些输出传递给任何命令

strace -f -t -e trace=file -p 8804 2>&1 | grep -oP "\"(.*)\".*O_WRONLY" | echo
# does not show anything

而且我无法保存所有这些的输出以供以后使用：

strace -f -t -e trace=file -p 8804 2>&1 | grep -oP "\"(.*)\".*O_WRONLY" > asd.out
# file is empty

感谢您的帮助。:)

Answer 1

您可以将输出写入文件（使用strace -o asd.out），然后 grep 它：

来自 strace 手册：

-o filename Write  the  trace  output to the file filename rather than 
to stderr.  Use filename.pid if -ff is used. If the argument begins with
`|' or with `!' then the rest of the argument is treated as a command
and all output is piped to it. This is convenient for piping the
debugging output to a program without affecting the redirections of 
executed programs.