我需要一个 shell 脚本，通过将逗号保留在引号内，将 csv 文件转换为管道 (|) 分隔的文件

Question

示例文件（test.csv）：

"PRCD-15234","CDOC","12","JUN-20-2016 17:00:00","title, with commas, ","Y!##!"
"PRCD-99999","CDOC","1","Sep-26-2016 17:00:00","title without comma","Y!##!"

输出文件：

PRCD-15234|CDOC|12|JUN-20-2016 17:00:00|title, with commas, |Y!##!
PRCD-99999|CDOC|1|Sep-26-2016 17:00:00|title without comma|Y!##!

我的脚本（不起作用）如下：

while IFS="," read f1 f2 f3 f4 f5 f6; 
do  
    echo $f1|$f2|$f3|$f4|$f5|$f6;  
done < test.csv

Answer 1

(generate output) | sed -e 's/","/|/g' -e 's/^"//' -e 's/"$//'

或者

sed -e 's/","/|/g' -e 's/^"//' -e 's/"$//' $file

对于 3 个表达式：

• -e 's/","/|/g' = 用","新的分隔符替换所有分隔符|

• -e 's/^"//' = 删除前导"标记

• -e 's/"$//' = 删除行尾"标记

这将保留任何碰巧在标题中的引号，只要它们与初始分隔符模式不匹配 ","