grep搜索+下一行

Question

通过grep命令，我找到了我需要的文本如下：

grep 'C02' ~/temp/log.txt 现在，无论我在哪里找到所需的字符串，我都想打印找到的字符串后面的行。

例如，假设所需的文本是“abc”，并且在第 12 行找到 abc，我也想打印第 13 行。

Answer 1

如果您使用的是Linux系统，您可以尝试：

grep -A1 "C02" ~/temp/log.txt


OPTIONS
       -A NUM, --after-context=NUM
              Print NUM lines of trailing context after matching lines.  Places a line containing -- between contiguous groups of matches.
       -B NUM, --before-context=NUM
              Print NUM lines of leading context before matching lines.  Places a line containing -- between contiguous groups of matches.
       -C NUM, --context=NUM
              Print NUM lines of output context.  Places a line containing -- between contiguous groups of matches.

您也可以将 awk 用作：

awk '/C02/{print;getline;print}' ~/temp/log.txt