如何为 zsh 中的特定目录编写自定义文件名完成程序？

Question

我发现标题前带有日期的文件名很难用制表符完成。我想为这些目录编写自定义完成函数。如何指定应使用完成者而不是默认值？

Answer 1

无法指定它，但您可以修补_path_files补全函数来实现此目的：

# Load the `functions` table.
zmodload -Fa zsh/parameter p:functions

# Load the definition of _path_files.
autoload +X -Uz _path_files

# Make a copy of it.
functions[_original_path_files]=$functions[_path_files]

# Replace the original.
_path_files() {
  # `$words[CURRENT]` is the current word under completion.
  # `:a` turns it into an absolute path.
  if [[ $words[CURRENT]:a == <pattern that matches the dirs in question>/* ]]; then
    <your special completion function> "$@"
  else
    _original_path_files "$@"
  fi
}

文档：

• zsh/parameter'functions稳定的
• 内置命令autoload
• 参数扩展修饰符