无法找出 shell 脚本意外操作符中的错误

Question

$ sh 备份到 s3.sh

backup-to-s3.sh: 11: [: bkup_20151106_150532.zip: unexpected operator
backup-to-s3.sh: 11: [: bkup_20151106_150532.zip: unexpected operator
backup-to-s3.sh: 11: [: bkup_20151106_150532.zip: unexpected operator
backup-to-s3.sh: 11: [: bkup_20151106_150532.zip: unexpected operator
backup-to-s3.sh: 11: [: bkup_20151106_150532.zip: unexpected operator
backup-to-s3.sh: 11: [: bkup_20151106_150532.zip: unexpected operator

ubuntu@accretive-staging-32gb-ephemeral:~$ cat backup-to-s3.sh

#Script to move /home/ubuntu/backup folder  to S3://auto-backup
#Author Ashish Karpe
cd /mnt/backup
filename="bkup_$(date +%Y%m%d_)"
/bin/ls -alF | awk '{ print $9 }'  > /tmp/file

for i in $(cat /tmp/file); do
#       echo $i;
#       read a;
#       echo $filename;
        if [ $filename* = $i ]
        then
                echo "Copying " $i "to S3://auto-backup";
                s3cmd put $i s3://auto-backup

            fi

done

Answer 1

1. 不要for用于遍历文件的行，请使用

   while IFS= read -r line; do ...; done < filename
   

2. 您根本不需要将ls输出通过管道传输到文件，尤其是使用-F

3. 使用 bash[[ x == y ]]进行模式比较，模式在右侧：

#!/bin/bash
cd /mnt/backup
prefix="bkup_$(date +%Y%m%d_)"

for file in * .*; do
    [[ -f $file ]] || continue    # skip things like directories and soft links
    if [[ $file == $prefix* ]]; then
        echo "Copying " $file "to S3://auto-backup";
        s3cmd put $file s3://auto-backup
    fi
done < /tmp/file