sed 命令来交换字符

Question

我的输入文件布局是：mm/dd/yyyy,hh:mm,other fields
我需要将其格式化为： yyyy-mm-dd hh:mm:00,other fields

样本输入：

01/02/1998,09:30,0.4571,0.4613,0.4529,0.4592,6042175
01/02/1998,09:45,0.4592,0.4613,0.4529,0.4571,9956023
01/02/1998,10:00,0.4571,0.4613,0.455,0.4613,8939555
01/02/1998,10:15,0.4613,0.4697,0.4571,0.4697,12823627
01/02/1998,10:30,0.4676,0.4969,0.4613,0.4906,28145145

示例输出：

1998-01-02 09:30:00,0.4571,0.4613,0.4529,0.4592,6042175
etc...

我尝试使用：

sed -r 's/\(^[0-9][0-9])\(\/[0-9][0-9]\/)\(\/[0-9][0-9][0-9][0-9],)/\3\1\2/g

Answer 1

sed -e 's/\(..\)\/\(..\)\/\(....\),\(.....\),\(.*\)/\3-\1-\2 \4:00,\5/'

编辑以包括来自以下评论的输入：

sed -e 's#\(..\).\(..\).\(....\),\(.....\),#\3-\1-\2 \4:00,#'