sda*_*aau 7 hexdump hex text-formatting
假设我有一个多行字符串,但上面的条目很短;如果我尝试 hexdump,那么我会得到这样的信息:
echo "something
is
being
written
here" | hexdump -C
#00000000 73 6f 6d 65 74 68 69 6e 67 0a 69 73 0a 62 65 69 |something.is.bei|
#00000010 6e 67 0a 77 72 69 74 74 65 6e 0a 68 65 72 65 0a |ng.written.here.|
#00000020
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大多数十六进制转储程序,包括hexdump
简单地用作 2D 矩阵(您可以定义每行将有多少字节/列);所以在这种情况下,整个输出被压缩在两行转储上。
有没有我可以使用的程序,它会像往常一样继续运行 - 除非遇到新行(0x0a
- 但可能是任何其他字符,或其序列),它也会开始一个新行?在这种情况下,我想像这样的输出:
00000000 73 6f 6d 65 74 68 69 6e 67 0a |something.|
0000000a 69 73 0a |is.|
0000000d 62 65 69 6e 67 0a |being.|
00000013 77 72 69 74 74 65 6e 0a |written.|
0000001b 68 65 72 65 0a |here.|
00000020
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嗯,有printf
...
hex_split()( unset c dump slice rad pend
_get(){ dd bs=1024 count=1; echo .; } 2>/dev/null
_buf() case $((${#dump}>0)):$((${#slice}>0)) in
(0:*) dump=$(_get); dump=${dump%.}
[ -n "$dump" ] || [ -n "$slice" ];;
(*:0) [ "${#dump}" -lt 16 ] &&
slice=${dump:-$slice} dump= && return
slice=${dump%"${dump#$q}"} dump=${dump#$q};;esac
_out(){ printf "%08x%02.0s" "$rad" "$((rad+=$#/2))"
printf "%02x %.0s" "$@"
printf "%-$(((16-($#/2))*3))s"
printf "%.0s%.1s" '' ' ' '' \| "$@" '' \| '' "$nl"
}; q=$(printf %016s|tr \ \?) ; IFS=\ nl='
' rad=0 c=0 split=${split:-$nl} slice="$*"; set --
while [ -n "$slice" ] || _buf || ! ${1:+"_out"} "$@" &&
c=${slice%"${slice#?}"} slice=${slice#?}
do set "$@" "'$c" "${c#[![:print:]]}."
case $#$c in (32*|*$split) _out "$@"; set --;;esac
done
)
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您可以将标准输入或参数或两者都交给它。所以...
echo "something
is
being
written
here" | hex_split something else besides
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...上面的打印...
00000000 73 6f 6d 65 74 68 69 6e 67 20 65 6c 73 65 20 62 |something else b|
00000010 65 73 69 64 65 73 00 73 6f 6d 65 74 68 69 6e 67 |esides.something|
00000020 0a |.|
00000021 69 73 0a |is.|
00000024 62 65 69 6e 67 0a |being.|
0000002a 77 72 69 74 74 65 6e 0a |written.|
00000032 68 65 72 65 0a |here.|
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更改默认的分割字符,例如...
split=${somechar} hex_split
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