使用 `case` 处理脚本参数

Question

我可以使用该case语句来处理参数吗？所以，使用 -restart 我想执行“-umount”和“-mount”

#!/bin/bash
case "$1" in
-mount
mount /ip/share1 /local/share1
;;
-umount
umount /ip/share1
;;
-restart
# echo TODO
;;
*)
[...]
esac

Answer 1

在我看来，这应该有效，除了缺少)s的语法狡辩。我对此进行了测试，它的行为正确..

#/bin/bash
case "$1" in
  "-mount")
    mount /path/to/device /path/to/mountpoint
    ;;
  "-unmount")
    umount /path/to/mountpoint
    ;;
  "-remount")
    "$0" -unmount
    "$0" -mount
    ;;
  *)
    echo "You have failed to specify what to do correctly."
    exit 1
    ;;
esac