格式化不带空格的“ps”命令输出

Question

我有以下ps命令来获取所有正在运行的进程的特定属性以及一些属性：

ps --no-headers -exo "uname,ppid,pid,etime,%cpu,%mem,args"

我希望将它格式化为 CSV 以便我可以解析它。注意我把 args 放在最后以方便解析；我不认为 a ,will 存在于任何其他列中 - 如果我错了，请纠正我。

如何去除空格？

Answer 1

从手册页：

-o format       user-defined format.
                format is a single argument in the form of a blank-separated or comma-separated list, which offers a
                way to specify individual output columns. The recognized keywords are described in the STANDARD FORMAT
                SPECIFIERS section below. Headers may be renamed (ps -o pid,ruser=RealUser -o comm=Command) as
                desired. If all column headers are empty (ps -o pid= -o comm=) then the header line will not be
                output. Column width will increase as needed for wide headers; this may be used to widen up columns
                such as WCHAN (ps -o pid,wchan=WIDE-WCHAN-COLUMN -o comm). Explicit width control
                (ps opid,wchan:42,cmd) is offered too. The behavior of ps -o pid=X,comm=Y varies with personality;
                output may be one column named "X,comm=Y" or two columns named "X" and "Y". Use multiple -o options
                when in doubt. Use the PS_FORMAT environment variable to specify a default as desired; DefSysV and
                DefBSD are macros that may be used to choose the default UNIX or BSD columns.

所以尝试：

/bin/ps -o uname:1,ppid:1,pid:1

Answer 2

由于前 6 个字段不应包含空白字符（除非您允许在用户名中使用它们），因此您可以对输出进行后处理：

ps --no-headers -exo "uname,ppid,pid,etime,%cpu,%mem,args" | sed '
  s/[\"]/\\&/g
  s/  */,/;s/  */,/;s/  */,/;s/  */,/;s/  */,/;s/  */,"/
  s/$/"/'

在使用 .s"和\s转义后引用最后一个字段（args）\。

产生如下输出：

stephane,3641,3702,10-00:20:24,0.1,0.3,"some cmd,and,args... VAR=foo\"bar"

Answer 3

您可以sed与 一起使用ps。所以你想要的就在这里：-

ps --no-headers -exo "uname,ppid,pid,etime,%cpu,%mem,args" | sed 's/\ /,/g'

但我想知道它是否有用，因为ps它本身的输出有很多,.