bash 运算符=~相当于perl调用吗？
filename="test-33.csv"
regex="([^.]+)(-\d{1,5})(\.csv)"
通过 bash 测试：
filename="test-33.csv"
regex="([^.]+)(-\d{1,5})(\.csv)"
和perl：
if [[ "$filename" =~ $regex ]]; then echo "it matches"; else echo "doesn't match"; fi
# doesn't match
if [[ "$filename" =~ ([^.]+)(-\d{1,5})(\.csv) ]]; then echo "matches"; else echo "doesn't match"; fi
# doesn't match
我对 bash 操作符有什么遗漏吗=~？这与贪婪与非贪婪迭代器 ( ) 有关系吗[^.]+？