Notepad++ 合并所有不以日期开头的行

Question

我 .csv在 Notepad++ 中有包含如下数据的文件：

1-6-2018,"(101)","","Sale",-862.96,,
"(Sale)",,837.96,
,"Diesel",12.000 Ltr,69.83/Ltr,837.96,
"Sales @ 5%",,23.80,
,"Polishing Cloth",1 Pcs,23.80/Pcs,23.80,
"CGST @ 2.5%",,0.60,
"SGST @ 2.5%",,0.60,
"(No. :16532)",
1-6-2018,"(149)","","Sale",-3212.18,,
"Sales(Sale)",,3212.18,
,"Diesel",46.000 Ltr,69.83/Ltr,3212.18,
"(No. :16533)",
// and many more

如何在 Notepad++ 中使用搜索和替换（或任何其他方法）来合并所有不以日期开头的行，因此最终结果如下所示？

1-6-2018,"(101)","","Sale",-862.96,,"(Sale)",,837.96,,"Diesel",12.000 Ltr,69.83/Ltr,837.96,"Sales @ 5%",,23.80,,"Polishing Cloth",1 Pcs,23.80/Pcs,23.80,"CGST @ 2.5%",,0.60,"SGST @ 2.5%",,0.60,"(No. :16532)",
1-6-2018,"(149)","","Sale",-3212.18,,"(Sale)",,3212.18,,"Diesel",46.000 Ltr,69.83/Ltr,3212.18,"(No. :16533)",

不以日期开头的每一行都与前一行合并...

Answer 1

• Ctrl+H
• 找什么： \R(?!\d{1,2}-\d{1,2}-\d{4})
• 用。。。来代替： LEAVE EMPTY
• 检查环绕
• 检查正则表达式
• Replace all

解释：

\R          : any kind of linebreak
(?!         : start negative look ahead, make sure we don't have after:
  \d{1,2}   : 1 or 2 digits
  -         : a dash
  \d{1,2}   : 1 or 2 digits
  -         : a dash
  \d{4}     : 4 digits
)           : end lookahead (ie. a date)

给定示例的结果：

1-6-2018,"(101)","","Sale",-862.96,,"(Sale)",,837.96,,"Diesel",12.000 Ltr,69.83/Ltr,837.96,"Sales @ 5%",,23.80,,"Polishing Cloth",1 Pcs,23.80/Pcs,23.80,"CGST @ 2.5%",,0.60,"SGST @ 2.5%",,0.60,"(No. :16532)",
1-6-2018,"(149)","","Sale",-3212.18,,"Sales(Sale)",,3212.18,,"Diesel",46.000 Ltr,69.83/Ltr,3212.18,"(No. :16533)",