Shell脚本在命令行中使用选项传递多个参数

Question

我有脚本，我需要像这样执行这个脚本：

./create_endpoint.sh --controller-ip 10.20.20.1 --controller-name User1.

但它的执行是这样的：

./create_endpoint.sh 10.20.20.1 User1

剧本：

CONTROLLER_IP=""
CONTROLLER_NAME=""
if [ "$#" -eq 2 ]
  then
    CONTROLLER_IP=$1
    CONTROLLER_NAME=$2
  else
    echo "Usage : create_endpoint.sh --controller-ip <Controller IP> --controller-name"
    exit 1  
fi
echo $CONTROLLER_IP
echo $CONTROLLER_NAME

Answer 1

我相信 usinggetopts是一种更好的提前使用解决方案，当您需要灵活处理传递的参数数量时。

这是一个工作示例：

if (($# == 0)); then
  echo "Please pass argumensts -p <pkg1><pkg2>... -m <email1><email2>.."
  exit 2
fi
while getopts ":p:m:" opt; do
  case $opt in
    p)
      echo "-p was triggered, Parameter: $OPTARG" >&2
      PKGS=$OPTARG
      ;;
    m)
      echo "-m was triggered, Parameter: $OPTARG" >&2
      MAIL=$OPTARG
      ;;
    \?)
      echo "Invalid option: -$OPTARG" >&2
      exit 1
      ;;
    :)
      echo "Option -$OPTARG requires an argument." >&2
      exit 1
      ;;
  esac
done
echo "go thru selection"
for PKG in $PKGS;
do
 echo "ARG_PKG: $PKG"
done
echo "go thru selection email"
for M in $MAIL;
do
 echo "ARG_MAIL: $M"
done
exit 0

参考.. http://wiki.bash-hackers.org/howto/getopts_tutorial

输出：

bash t -p "pkg1 pkg2 pkg3" -m "bobo@m.com boba@m.com"
-p was triggered, Parameter: pkg1 pkg2 pkg3
-m was triggered, Parameter: bobo@m.com boba@m.com
go thru selection
ARG_PKG: pkg1
ARG_PKG: pkg2
ARG_PKG: pkg3
go thru selection email
ARG_MAIL: bobo@m.com
ARG_MAIL: boba@m.com