如何在根文件夹的每个子目录中列出一个文件？

Question

抱歉，如果这是微不足道的 - 但如何在我的根文件夹的每个子目录中只列出一个文件？Linux 终端或 MS DOS 语法无关紧要。我猜这将是一个带有一些参数的 ls 或 dir 命令，但我在手册中没有找到任何命令的任何内容。

Answer 1

写了一个小脚本来做到这一点。

#!/bin/bash
for dir in `find . -type d` # Find directories recursively
do
  # cd into directory, quotes are for directory names with spaces
  cd "$dir"             

  # Print out directory name
  echo "In directory $dir:"

  # Force list output to be one entry per line, pipe through inverted grep to 
  # exclude directories, pipe through awk to get the first item. You can specify
  # the number of files you want.     
  ls -p1 | grep -v / | awk -v "num_of_files=1" 'NR<=num_of_files { print $1 }'

  # cd back to root directory
  cd "$OLDPWD"              
done

输出：

In directory .:
test.sh
In directory ./bar:
barfile.txt
In directory ./baz:
bazfile.txt
In directory ./baz/quux:
something.txt
In directory ./foo:
foofile.txt