我看到很多关于这个的问题,并试图解决这个问题,但经过一个小时的谷歌搜索和大量的试验和错误,我仍然无法解决它.我希望你们中的一些人能够解决问题.
这就是我得到的:
java.lang.IllegalArgumentException: Comparison method violates its general contract!
at java.util.ComparableTimSort.mergeHi(ComparableTimSort.java:835)
at java.util.ComparableTimSort.mergeAt(ComparableTimSort.java:453)
at java.util.ComparableTimSort.mergeForceCollapse(ComparableTimSort.java:392)
at java.util.ComparableTimSort.sort(ComparableTimSort.java:191)
at java.util.ComparableTimSort.sort(ComparableTimSort.java:146)
at java.util.Arrays.sort(Arrays.java:472)
at java.util.Collections.sort(Collections.java:155)
...
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这是我的比较器:
@Override
public int compareTo(Object o) {
if(this == o){
return 0;
}
CollectionItem item = (CollectionItem) o;
Card card1 = CardCache.getInstance().getCard(cardId);
Card card2 = CardCache.getInstance().getCard(item.getCardId());
if (card1.getSet() < card2.getSet()) {
return -1;
} else {
if (card1.getSet() == card2.getSet()) {
if (card1.getRarity() < card2.getRarity()) {
return 1;
} else {
if (card1.getId() == card2.getId()) { …
Run Code Online (Sandbox Code Playgroud) 如何在使用Spring Cloud AWS的Spring启动应用程序中禁用Cloudformation?
在亚马逊上运行我的应用程序时,我一直收到此错误:
...
Caused by: org.springframework.beans.BeanInstantiationException: Failed to instantiate [org.springframework.cloud.aws.core.env.stack.config.StackResourceRegistryFactoryBean]: Factory method 'stackResourceRegistryFactoryBean' threw exception; nested exception is com.amazonaws.AmazonServiceException: Stack for i-b5ce9e32 does not exist (Service: AmazonCloudFormation; Status Code: 400; Error Code: ValidationError; Request ID: 75b3076a-176d-11e6-90cc-b55a643dc6d6)
at org.springframework.beans.factory.support.SimpleInstantiationStrategy.instantiate(SimpleInstantiationStrategy.java:189)
at org.springframework.beans.factory.support.ConstructorResolver.instantiateUsingFactoryMethod(ConstructorResolver.java:588)
... 82 more
Caused by: com.amazonaws.AmazonServiceException: Stack for i-b5ce9e32 does not exist (Service: AmazonCloudFormation; Status Code: 400; Error Code: ValidationError; Request ID: 75b3076a-176d-11e6-90cc-b55a643dc6d6)
at com.amazonaws.http.AmazonHttpClient.handleErrorResponse(AmazonHttpClient.java:1389)
at com.amazonaws.http.AmazonHttpClient.executeOneRequest(AmazonHttpClient.java:902)
at com.amazonaws.http.AmazonHttpClient.executeHelper(AmazonHttpClient.ja
...
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我不想使用cloudformation.(至少现在(是.)
java spring amazon-web-services spring-cloud spring-cloud-aws
我正在将代码迁移到 Java 20。
\n在此版本中,java.net.URL#URL(java.lang.String)已被弃用。不幸的是,我在一个类中找不到旧 URL 构造函数的替代品。
\npackage com.github.bottomlessarchive.loa.url.service.encoder;\n\nimport io.mola.galimatias.GalimatiasParseException;\nimport org.springframework.stereotype.Service;\n\nimport java.net.MalformedURLException;\nimport java.net.URI;\nimport java.net.URISyntaxException;\nimport java.net.URL;\nimport java.util.Optional;\n\n/**\n * This service is responsible for encoding existing {@link URL} instances to valid\n * <a href="https://en.wikipedia.org/wiki/Internationalized_Resource_Identifier">resource identifiers</a>.\n */\n@Service\npublic class UrlEncoder {\n\n /**\n * Encodes the provided URL to a valid\n * <a href="https://en.wikipedia.org/wiki/Internationalized_Resource_Identifier">resource identifier</a> and return\n * the new identifier as a URL.\n *\n * @param link the url to encode\n * @return the encoded url\n */\n public Optional<URL> encode(final String …
Run Code Online (Sandbox Code Playgroud) 如何更改TableView组件标题的文本颜色?
我累了这个:
.table-view .column-header, .table-view .filler {
-fx-text-fill: white;
-fx-border-width: 0, 0;
-fx-font-size: 12px;
}
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这会删除边框,也会更改字体大小,但不会更改字体颜色.
如何从FXML设置TableView的调整大小策略?我这样累了,但它不起作用:
<TableView layoutX="20.0" layoutY="20.0" prefWidth="674.0" prefHeight="668.0" fx:id="tableView" fx:constant="CONSTRAINED_RESIZE_POLICY">
<columns>
<TableColumn text="First Name" />
<TableColumn text="Last Name" />
<TableColumn text="Email Address" />
</columns>
</TableView>
Run Code Online (Sandbox Code Playgroud) 我需要将"匈牙利语","英语"等语言名称转换为ISO 639代码.ISO 639-6将是最好的,但ISO 639-2已经足够好了.实现这一目标的最佳方法是什么?
我应该将英语转换为语言环境并使用getLanguage()获取语言?如果这是唯一的方法如何将像'English'这样的字符串转换为java语言环境?
我的目标是使用ISO 639代码存储书籍语言信息.
如何在JavaFX 2中设置/获取光标的位置?我累了谷歌搜索答案,但没有发现任何有用的东西.我所能做的就是设置光标的样式.
如何在JavaFX 2中创建自动换行ListView(文本太长时多行)?我知道如果我把\n放在字符串上,它将是多行的,但内容太动态了.或者有一个很好的方法在每个'xyz'像素长度之后将\n放到String中.
谢谢!
我尝试在 spring-boot 应用程序中使用 liquibase 将一行插入到 mysql 中。与此类似的东西:
<databaseChangeLog
xmlns="http://www.liquibase.org/xml/ns/dbchangelog/1.9"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://www.liquibase.org/xml/ns/dbchangelog/1.9
http://www.liquibase.org/xml/ns/dbchangelog/dbchangelog-1.9.xsd">
<changeSet author="laxika" id="20160508-2">
<insert tableName="news">
<column name="title" value="Hello world"/>
<column name="release_date" value="2016-05-09 00:00:00"/>
<column name="icon" value="update"/>
<column name="message" value="
a
b
c
d
"/>
</insert>
</changeSet>
</databaseChangeLog>
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由于一些奇怪的原因,liquibase 没有正确地将换行符添加到 sql 中,所以我最终在数据库中有一个长字符串。如何强制 liquibase 插入换行符?
这是我尝试插入的表的架构:
<databaseChangeLog
xmlns="http://www.liquibase.org/xml/ns/dbchangelog/1.9"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://www.liquibase.org/xml/ns/dbchangelog/1.9
http://www.liquibase.org/xml/ns/dbchangelog/dbchangelog-1.9.xsd">
<changeSet author="laxika" id="20150922-4">
<createTable tableName="news">
<column name="id" type="smallint unsigned" autoIncrement="true">
<constraints primaryKey="true" nullable="false" />
</column>
<column name="release_date" type="date">
<constraints nullable="false" />
</column>
<column name="title" type="varchar(256)">
<constraints nullable="false" />
</column> …
Run Code Online (Sandbox Code Playgroud) 对于同一问题,我有两种解决方案,但我不确定从长远来看哪种解决方案更适合使用。
控制器是:
@RequestMapping(value = "/skill/leatherworking/curing/start", method = RequestMethod.POST)
public Response startCuring(final UserEntity userEntity, @RequestBody @Valid final CuringCreateRequest curingCreateRequest) {
final CuringResult result = curingService.cure(userEntity, recipeDefinitionCache.getDefinition(curingCreateRequest.getRecipeId()));
...
}
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域对象是:
public class CuringCreateRequest {
@Min(1)
private int recipeId;
...
}
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控制器是:
@RequestMapping(value = "/skill/leatherworking/curing/start", method = RequestMethod.POST)
public Response startCuring(final UserEntity userEntity, @Valid final CuringCreateRequest curingCreateRequest) {
final CuringResult result = curingService.cure(userEntity, curingCreateRequest.getRecipe());
...
}
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这里我们还有一个HandlerMethodArgumentResolver:
public class RequestContextHandlerMethodArgumentResolver implements HandlerMethodArgumentResolver {
/**
* {@inheritDoc}
*/
@Override
public boolean supportsParameter(final …
Run Code Online (Sandbox Code Playgroud) 即使将内存大小设置为32 GB并仅将500 MB文件读入构建器,我也会从java.lang.StringBuilder.append中收到OutOfMemoryError。
java.lang.OutOfMemoryError: null
at java.base/java.lang.AbstractStringBuilder.hugeCapacity(AbstractStringBuilder.java:214) ~[na:na]
at java.base/java.lang.AbstractStringBuilder.newCapacity(AbstractStringBuilder.java:206) ~[na:na]
at java.base/java.lang.AbstractStringBuilder.ensureCapacityInternal(AbstractStringBuilder.java:173) ~[na:na]
at java.base/java.lang.AbstractStringBuilder.append(AbstractStringBuilder.java:538) ~[na:na]
at java.base/java.lang.StringBuilder.append(StringBuilder.java:174) ~[na:na]
at com.github.loa.indexer.service.index.base64.Base64Encoder.encode(Base64Encoder.java:31) ~[classes/:na]
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