为了简化我的问题：假设我有3张桌子。
Rooms People Things
-------- -------- --------
id| name id | name | fk_rooms id | name | fk_rooms
----------- --------------------- ---------------------
1 | kitchen 1 | John | 1 1 | TV | 2
2 | bedroom 2 | Mary | 2 2 | bed | 2
3 | Andy | 1 3 | sink | 1
4 | Laura| 1
现在我正在做类似的事情：
SELECT r.name AS room_name, p.name AS name, t.name AS thing FROM Rooms r
LEFT JOIN People p …