Python是一种解释型语言,所以它在我运行时逐行执行代码
import csv,re,sys
print len(sys.argv)
if(len(sys.argv)!=2):
sys.exit(0)
filename= #from command line argument
它甚至不执行一行并给出语法错误.
现在我的问题是代码的最后一行有错误,但Python解释器逐行执行代码行这样的代码到最后一行是正确的,所以应该高达最后一行执行代码,但它给我下面的错误和不打印我在第2行中定义的sys.argv的长度
File "trace-analysis.py", line 45
filename = # from command line argument
SyntaxError: invalid syntax
我没有得到这种行为......请有人解释一下......
谁能告诉我这个代码中的[抄送]是什么？我知道它做了什么,但我不知道它叫什么.
#!/usr/bin/perl
$sentence = "Big cat sat.";
$sentence =~ /[Cc]at/;
print "$`, $&, $'\n"; #prints Big, cat, sat.
也有人知道什么是python 2.7的re.search的perl等价物？我一直在寻找的是关于python的替换是可变的,并没有真正说到搜索.
我是一个初学者，没有太多的编码知识。我正在尝试运行以下python脚本... https://github.com/Sdocquir/moneyonbots/blob/master/shopify3/shopify3.py
这样做时，我收到以下消息
/Users/xxx/Downloads/moneyonbots-master/shopify3/shopify3.py: line 1: __author__: command not found
/Users/xxx/Downloads/moneyonbots-master/shopify3/shopify3.py: line 3: import: command not found
/Users/xxx/Downloads/moneyonbots-master/shopify3/shopify3.py: line 4: import: command not found
/Users/xxx/Downloads/moneyonbots-master/shopify3/shopify3.py: line 5: import: command not found
/Users/xxx/Downloads/moneyonbots-master/shopify3/shopify3.py: line 6: import: command not found
/Users/xxx/Downloads/moneyonbots-master/shopify3/shopify3.py: line 7: import: command not found
/Users/xxx/Downloads/moneyonbots-master/shopify3/shopify3.py: line 8: import: command not found
from: can't read /var/mail/lxml
from: can't read /var/mail/selenium
from: can't read /var/mail/requests.adapters
/Users/xxx/Downloads/moneyonbots-master/shopify3/shopify3.py: line 15: syntax error near unexpected token `('
/Users/xxx/Downloads/moneyonbots-master/shopify3/shopify3.py: line 15: modes = [('Gift Card', …我有一个文件,其中包含我要删除的路径列表.
rm在每个路径前添加(以生成将运行这些删除的脚本)似乎是显而易见的方法.我怎样才能做到这一点？
我有一个大学的 BASH 项目，有两个我不明白的错误
这是我的脚本 BASH ：
#!/bin/bash
proc_name=`cat /proc/cpuinfo | grep 'model name' | cut -d':' -f2 |cut -d'@' -f1 | uniq`;
proc_freq=`cat /proc/cpuinfo | grep 'model name' | cut -d':' -f2 |cut -d'@' -f2 | uniq`;
proc_core=`cat /proc/cpuinfo | grep 'cpu cores' | cut -d':' -f2 | uniq`;
proc_hyperthreading=`cat /proc/cpuinfo | grep 'siblings' | cut -d':' -f2 | uniq`;
proc_architecture=`lscpu | grep '64-bit' | cut -d',' -f2 | cut -d'-' -f1`;
proc_cache_L1=`lscpu | grep 'Cache L1i' | cut -d':' …我如何将“ 0.00”转换为整数而不invalid literal for int() with base 10: '0.00'出错？
这是我当前的代码；
a = int('0.00') # which gives me an error
a = int(float('0.00')) # gives me 0, not the correct value of 0.00
任何建议，将不胜感激！