我有一些用Oracle编写的程序.不幸的是我无法显示其代码.其中的某个地方是由于缺少必需的数据而选择执行崩溃的地方.看起来像这样

select value into l_value
        from config
       where code = upper(p_code);

所以当我这样调用这个过程时(在SqlDeveloper中)

execute some_package.some_procedure('CODE');

它抛出

Error report -
ORA-01403: no data found
ORA-06512: at "XXXXXXXXXXXXXXXXXXX", line 111
ORA-06512: at "XXXXXXXXXXXXXXXXXXX", line 111
ORA-06512: at line 1
01403. 00000 -  "no data found"
*Cause:    No data was found from the objects.
*Action:   There was no data from the objects which may be due to end of fetch.

但是当我这样称呼它时

call some_package.some_procedure('CODE');

它崩溃在同一个地方(我可以从结果中建议,存储在DB中),但它没有抛出异常.

some_package.some_procedure('CODE') succeeded.

怎么了？为什么会有这样的差异？

简要

我需要通过密钥的动态名称对映射/属性进行空安全访问.Map本身可以为null.我想出了map?.(keyName)但是想知道为什么它不能像预期的那样起作用并且总是回归null

代码示例

def map = [key: 'value']
def keyName = 'key'

map.each({ key, value -> println("[${key.class}]: [${value.class}]")})
println("keyName class is [${keyName.class}]")

println(map?.(keyName))                        // null  <--------- My question

// Alternatives that work well
println(map?.(keyName as String))              // value
println(map?.(keyName as java.lang.String))    // value
println(map?.get(keyName))                     // value

?

产量

[class java.lang.String]: [class java.lang.String]
keyName class is [class java.lang.String]
null
value
value
value

题

如果两者keyName和地图键都是类型,java.lang.String为什么map?.(keyName)不返回值？为何map?.(keyName as String)回归？

链接

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