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我在配置文件中有一个 URL，我使用 ConfigParser 解析该 URL 以获取请求

配置文件

[default]
root_url ='https://reqres.in/api/users?page=2'

FetchFeeds.py

import requests
from configparser import ConfigParser
import os
import requests


config = ConfigParser()
config.read(os.path.join(os.path.dirname(__file__), '../Config', 'config.ini'))
rootUrl = (config['default']['root_url'])
print(rootUrl)
response = requests.get(rootUrl)

即使 URL 打印正确'https://reqres.in/api/users?page=2'，但我在请求模块上收到以下错误

Traceback (most recent call last):
  File "C:/Users/sam/PycharmProjects/testProject/GET_Request/FetchFeeds.py", line 11, in <module>
    response = requests.get(rootUrl)
  File "C:\Users\sam\PycharmProjects\testProject\venv\lib\site-packages\requests\api.py", line 76, in get
    return request('get', url, params=params, **kwargs)
  File "C:\Users\sam\PycharmProjects\testProject\venv\lib\site-packages\requests\api.py", line 61, in request
    return session.request(method=method, url=url, **kwargs)
  File "C:\Users\sam\PycharmProjects\testProject\venv\lib\site-packages\requests\sessions.py", line 530, in request …