有两个DataFrame(Scala,Apache Spark 1.6.1)
1)比赛
MatchID | Player1 | Player2
--------------------------------
1 | John Wayne | John Doe
2 | Ive Fish | San Simon
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2)个人资料
Player | BirthYear
--------------------------------
John Wayne | 1986
Ive Fish | 1990
San Simon | 1974
john Doe | 1995
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如何为两个玩家创建一个带有'BirthYear'的新DataFrame
MatchID | Player1 | Player2 | BYear_P1 |BYear_P2 | Diff
-------------------------------------------------------------
1 | John Wayne | John Doe | 1986 | 1995 | 9
2 | Ive Fish | San Simon | 1990 | …Run Code Online (Sandbox Code Playgroud) 如何通过SPARQL端点阻止我的OpenRDF Sesame 2.6.5 RDF存储从修改(INSERT/DELETE)?
"选择"查询将通过POST请求完成.
禁止(通过Apache Tomcat配置文件,用于Sesame的WAR)以下SPARQL HTTP端点URL:
http:/ localhost:8080/openrdf-sesame/repositories/test/update ...
和
http:/ localhost:8080/openrdf-workbench/repositories/test/update ...?
我有一个 CSV 文件(未标准化,例如,最多 100 列的真实文件):
ID, CUST_NAME, CLIENT_NAME, PAYMENT_NUM, START_DATE, END_DATE
1, CUST1, CLIENT1, 10, 2018-04-01, 2018-04-02
2, CUST1, CLIENT1, 10, 2018-04-01, 2018-05-30
3, CUST1, CLIENT1, 101, 2018-04-02, 2018-04-03
4, CUST2, CLIENT1, 102, 2018-04-02, 2018-04-03
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如何找到可以用作主键的所有可能的列集。
期望的输出:
1) ID
2) PAYMENT_NUM,START_DATE,END_DATE
3) CUST_NAME, CLIENT_NAME, PAYMENT_NUM,START_DATE,END_DATE
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我可以用 Java 来做,但可能 Python/Pandas 已经提供了一个快速解决方案
我知道WordNet有域名层次结构:例如sport-> football.
1)是否可以列出所有相关的单词,例如,"sport-> football"子域?
Response: goalkeeper, forward, penalty, ball, field, stadium, referee and so on.
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2)获取给定单词的域名,例如"守门员"?
Need something like [sport->football; sport->hockey] or [football;hockey] or just 'football'.
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它用于文档分类任务.
nlp semantic-web cluster-analysis wordnet document-classification
如何从IBM Bluemix中部署的应用程序将日志文件下载到本地计算机(Windows)?
cf download APPNAME
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不再起作用了.
我知道我可以通过它查看
cf ssh
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但它很大.