因此,正如标题所希望的那样,这是在所述书中的一个例子.我还是编程新手,调试困难.对此表示欢迎任何批评,特别是如果它显示更有效的编码方式; 请记住,我仍然是新手,所以如果你给我一个新的内置功能或某些东西,我很可能不知道你指的是什么.
因此,本练习的目的是编写一个函数,给它三个参数,以确定这三个参数是否形成一个三角形.这是我的代码:
def is_triangle(a,b,c):
num_list = [a,b,c]
biggest = max(num_list)
other_two = num_list.remove(biggest)
sum_of_two = sum(other_two)
if sum_of_two > biggest:
print 'Congrats, %d, %d, and %d form a triangle!' % (a,b,c)
elif sum_of_two == biggest:
print 'That forms a degenerate triangle!'
else:
print 'That does\'t make any sort triangle... >:['
def sides():
side1 = raw_input('Please input side numero Juan: ')
side2 = raw_input('Now side two: ')
side3 = raw_input('...aaaannnd three: ')
import time
time.sleep(1)
print 'Thanks >:]'
side1 = …Run Code Online (Sandbox Code Playgroud) 我有一个庞大的列表,我需要处理,这需要一些时间,所以我把它分成4件,并用一些功能多处理每件.使用4个内核运行仍然需要一些时间,所以我想我会在函数中添加一些进度条,以便它可以告诉我处理列表时每个处理器的位置.
我的梦想是拥有这样的东西:
erasing close atoms, cpu0 [######..............................] 13%
erasing close atoms, cpu1 [#######.............................] 15%
erasing close atoms, cpu2 [######..............................] 13%
erasing close atoms, cpu3 [######..............................] 14%
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每个条随着函数循环的移动而移动.但相反,我得到一个持续的流程:
等等,填满我的终端窗口.
这是调用函数的主要python脚本:
from eraseCloseAtoms import *
from readPDB import *
import multiprocessing as mp
from vectorCalc import *
prot, cell = readPDB('file')
atoms = vectorCalc(cell)
output = mp.Queue()
# setup mp to erase grid atoms that are too close to the protein (dmin = 2.5A)
cpuNum = 4
tasks = len(atoms)
rangeSet = …Run Code Online (Sandbox Code Playgroud) 我试图在我的HTML中使用复选框,将这些复选框返回到我的python后端,然后如果单击该框,则递增三个计数器.
现在我的HTML如下,工作正常:
<form method="post">
<input type="checkbox inline" name="adjective" value="entertaining">Entertaining
<input type="checkbox inline" name="adjective" value="informative">Informative
<input type="checkbox inline" name="adjective" value="exceptional">Exceptional
</form>
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然后在我的python后端我有以下内容:
def post(self):
adjective = self.request.get('adjective ')
if adjective :
#somehow tell if the entertaining box was checked
#increment entertaining counter
#do the same for the others
Run Code Online (Sandbox Code Playgroud) 我正在构建一个具有类变量字典的模块:
class CodonUsageTable:
CODON_DICT={'TTT': 0, 'TTC': 0, 'TTA': 0, 'TTG': 0, 'CTT': 0,
'CTC': 0, 'CTA': 0, 'CTG': 0, 'ATT': 0, 'ATC': 0,
'ATA': 0, 'ATG': 0, 'GTT': 0, 'GTC': 0, 'GTA': 0,
'GTG': 0, 'TAT': 0, 'TAC': 0, 'TAA': 0, 'TAG': 0,
'CAT': 0, 'CAC': 0, 'CAA': 0, 'CAG': 0, 'AAT': 0,
'AAC': 0, 'AAA': 0, 'AAG': 0, 'GAT': 0, 'GAC': 0,
'GAA': 0, 'GAG': 0, 'TCT': 0, 'TCC': 0, 'TCA': 0,
'TCG': 0, 'CCT': 0, 'CCC': 0, 'CCA': …Run Code Online (Sandbox Code Playgroud) 我正在观察Python 3.3.4中我希望帮助理解的行为:为什么在正常执行函数时正确引发异常,而不是在函数池中执行函数时?
import multiprocessing
class AllModuleExceptions(Exception):
"""Base class for library exceptions"""
pass
class ModuleException_1(AllModuleExceptions):
def __init__(self, message1):
super(ModuleException_1, self).__init__()
self.e_string = "Message: {}".format(message1)
return
class ModuleException_2(AllModuleExceptions):
def __init__(self, message2):
super(ModuleException_2, self).__init__()
self.e_string = "Message: {}".format(message2)
return
def func_that_raises_exception(arg1, arg2):
result = arg1 + arg2
raise ModuleException_1("Something bad happened")
def func(arg1, arg2):
try:
result = func_that_raises_exception(arg1, arg2)
except ModuleException_1:
raise ModuleException_2("We need to halt main") from None
return result
pool = multiprocessing.Pool(2)
results = pool.starmap(func, [(1,2), (3,4)])
pool.close()
pool.join() …Run Code Online (Sandbox Code Playgroud) 我有一个应用程序,以下列方式创建一个快捷方式:
Intent shortcutIntent = new Intent(this, MYWEBVIEW.class);
String fileHtml = trovaHtml(path);
shortcutIntent.putExtra("appToLaunch", appId);
shortcutIntent.putExtra("fileHtml", fileHtml);
shortcutIntent.setAction(Intent.ACTION_VIEW);
Intent addIntent = new Intent();
addIntent.putExtra(Intent.EXTRA_SHORTCUT_INTENT, shortcutIntent);
addIntent.putExtra(Intent.EXTRA_SHORTCUT_NAME, dirAppName);
addIntent.putExtra(Intent.EXTRA_SHORTCUT_ICON_RESOURCE,
Intent.ShortcutIconResource.fromContext(this, R.drawable.icon));
addIntent.setAction("com.android.launcher.action.INSTALL_SHORTCUT");
this.sendBroadcast(addIntent);
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我知道这段代码已被弃用但让我们忘了它.......
MYWEBVIEW不是我的应用程序的主要活动,是打开离线html页面的webview,并且此html文件的路径在额外值"fileHtml"内.
当我点击快捷方式时,我收到此错误:
08-08 14:15:37.907:ERROR/Launcher(165):启动器没有启动Intent的权限{act = android.intent.action.VIEW flg = 0x10000000 cmp = market.finestraprincipale/.MyAppActivity bnds = [3,217] ] [77,296](有额外的)}.确保为相应的活动创建MAIN intent-filter或使用此活动的导出属性.tag = ShortcutInfo(title = myFile)intent = Intent {act = android.intent.action.VIEW flg = 0x10000000 cmp = market.finestraprincipale/.MYWEBVIEW bnds = [3,217] [77,296](有额外内容)}
08-08 14:15:37.907:ERROR/Launcher(165):java.lang.SecurityException:Permission Denial:start Intent {act = android.intent.action.VIEW flg = 0x10000000 cmp = …
我正在尝试编写一个Python函数,它将两个列表作为参数并对它们进行交错.应保留组件列表的顺序.如果列表的长度不同,则较长列表的元素应最终位于结果列表的末尾.例如,我想把它放在Shell中:
interleave(["a", "b"], [1, 2, 3, 4])
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得到这个:
["a", 1, "b", 2, 3, 4]
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如果你能帮助我,我会很感激.
这个python源代码有什么问题?
import threading
import subprocess as sub
def ben(fil):
pr = sub.Popen(fil,stdout=sub.PIPE,stderr=sub.PIPE)
output, errors = pr.communicate()
print output
theapp = '''blender
blender-softwaregl'''.split()
print theapp
for u in theapp:
print u
tr = threading.Thread(target=ben, args=(u))
tr.daemon = True
tr.start()
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错误是:
['blender', 'blender-softwaregl']
blender
Exception in thread Thread-1:
Traceback (most recent call last):
File "/usr/local/lib/python2.7/threading.py", line 551, in __bootstrap_inner
self.run()
File "/usr/local/lib/python2.7/threading.py", line 504, in run
self.__target(*self.__args, **self.__kwargs)
TypeError: ben() takes exactly 1 argument (7 given)
blender-softwaregl
Exception in thread Thread-2:
Traceback …Run Code Online (Sandbox Code Playgroud) 我正在构建一个双向链表,我正在努力在PYTHON中构造一个双向链表迭代器方法.
到目前为止这是我的代码
class DoubleListNode:
def __init__(self,data):
self.data=data
self.prev = None
self.next= None
class ListIterator:
def __init__(self):
self._current = self.head
def __iter__(self):
return self
def next(self):
if self.size == 0 :
raise StopIteration
else:
item = self._current.data
self._current=self._current.next
return item
class DoublyLinkedList:
def __init__(self):
self.head= None
self.tail= None
self.size = 0
def add(self,data):
newnode= DoubleListNode(data)
self.size+=1
if self.head is None:
self.head = newnode
self.tail = self.head
elif data < self.head.data: # before head
newnode.next = self.head
self.head.prev= newnode
self.head= …Run Code Online (Sandbox Code Playgroud) 我是编程的新手,过去几个月我一直在闲暇时间学习python.我决定尝试创建一个小脚本,在文本文件中将美国拼写转换为英语拼写.
在过去的5个小时里,我一直在尝试各种各样的事情,但最终想出的东西让我更接近我的目标,但并不完全在那里!
#imported dictionary contains 1800 english:american spelling key:value pairs.
from english_american_dictionary import dict
def replace_all(text, dict):
for english, american in dict.iteritems():
text = text.replace(american, english)
return text
my_text = open('test_file.txt', 'r')
for line in my_text:
new_line = replace_all(line, dict)
output = open('output_test_file.txt', 'a')
print >> output, new_line
output.close()
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我确信有一个更好的方法可以解决问题,但对于这个脚本,这里是我遇到的问题:
任何帮助赞赏这个渴望新手!
test_file.txt的内容是:
I am sample file.
I contain an english spelling: colour.
3 american spellings on 1 line: color, analyze, utilize.
1 american spelling on 1 line: …Run Code Online (Sandbox Code Playgroud) python ×9
python-2.7 ×5
android ×1
checkbox ×1
class ×1
dictionary ×1
exception ×1
html ×1
nonetype ×1
numpy ×1
permissions ×1
python-3.x ×1
python-click ×1
webapp2 ×1