我有一个包含以下文本块的文件。我在文本块之前和之后都有文本
other_user:
hash: JKJ;LKJA;LDKJF;LKJA;LKJIUR;JFKLJDQPIRQKJ;LKFJPOQJ
#password is: some_pw0
logstash:
hash: $fj;kdjjfajf;ajKFJ;dfj;dkfja;dfjFJ:LFJj;kj;lfkajs
#password is: some_pw
other_user1:
hash: JJKLJDRKJOPIQMVOIUROIJFAUROJJFIUQWKERJJFKQURJAKDJ
#password is: some_pw1
我正在尝试使用此代码删除 logstash 用户的块，但它没有删除它。
- name: Delete existing logstash user
blockinfile:
dest: /path_to_file/foo.yml
state: absent
block: |
logstash:
hash: $fj;kdjjfajf;ajKFJ;dfj;dkfja;dfjFJ:LFJj;kj;lfkajs
#password is: some_pw
我希望结果是：
other_user:
hash: JKJ;LKJA;LDKJF;LKJA;LKJIUR;JFKLJDQPIRQKJ;LKFJPOQJ
#password is: some_pw0
other_user1:
hash: JJKLJDRKJOPIQMVOIUROIJFAUROJJFIUQWKERJJFKQURJAKDJ
#password is: some_pw1
我错过了什么？
在这里很棒的帖子的帮助下,我理解错误.但是我需要澄清一下.
假设我的托管对象上下文(模式)有3个表(实体),并且说每个实体有3个属性,其中每个条目的一个属性不是可选的.
所以现在我的应用程序第一次为第一个实体创建一个托管对象,填充其强制属性; app还没有为第二个和第三个实体创建托管对象 - 还没有.当我尝试在此时保存上下文时,我得到错误代码1570.是因为我没有填写第二个和第三个实体的值吗？
我知道sed语法在文件中的另一行之后添加一行,即
sed -i '/LINE1/a LINE2' FILE
在FILE中LINE1之后添加LINE2是否正确？如何在末尾添加带反斜杠的行？例如,来自
This is a a line \
Indented line1 \
Indented line2 \
Line3
至
This is a a line \
Indented line1 \
Indented line2 \
Added line \
Line3
Ansible v2.4.0.0
我正在安装Gitlab-CE，在Ansible任务中运行以下命令。如您所见，某些进程已关闭，但最终会启动。
# gitlab-ctl status
run: gitlab-workhorse: 0s, normally up
run: logrotate: 1s, normally up
down: nginx: 0s, normally up
down: postgresql: 1s, normally up
run: redis: 0s, normally up
run: sidekiq: 0s, normally up
run: unicorn: 0s, normally up
如何编写Ansible wait_for任务来检查所有服务何时都处于运行状态？IOW我只想看到下一个任务就继续下一个任务
# gitlab-ctl status
run: gitlab-workhorse: 0s, normally up
run: logrotate: 1s, normally up
run: nginx: 0s, normally up
run: postgresql: 1s, normally up
run: redis: 0s, normally up
run: sidekiq: 0s, normally up
run: unicorn: 0s, normally …我有以下代码
#!/usr/local/homebrew/bin/groovy
def jobs = ['Groovy', 'Rocks', 'Big', 'Time']
def generateStage(String service, Integer sleepTime=0) {
return {
sleep sleepTime
println "Hello $service"
}
}
Map generateStageMap(List list) {
Integer sleepTime = 0
Map stageMap = [:]
list.each {
stageMap[it] = generateStage(it, sleepTime)
// slightly staggered starts so we don't have too many
// request per sec to the CLI
sleepTime += 5
}
return stageMap
}
Map map = generateStageMap(jobs)
map.each {
it.value
}
我如何让它执行 println 语句使输出看起来像这样？
Hello Groovy
Hello …我稍后会更新，但现在...
$ terraform --version
Terraform v0.12.17
+ provider.aws v3.23.0
./aws/credentials我在我的和文件中设置了 AWS 配置文件~/.aws/config，就像这样......
~/.aws/credentials
[default]
aws_access_key_id=****
aws_secret_access_key=****
[myprofile]
aws_access_key_id=****
aws_secret_access_key=****
~/.aws/config
[default]
region=us-east-1
output=json
[profile myprofile]
region=us-east-1
output=json
在我的 Terraform 计划中，我有
provider "aws" {
region = "us-east-1"
profile = "myprofile"
}
terraform {
required_version = ">= 0.12.17, < 0.13"
}
resource "aws_vpc" "vpc" {
cidr_block = "10.123.123.0/24"
tags = {
Name = "test_vpc"
}
}
output "vpc_id" {
value = aws_vpc.vpc.id
}
我有一个创建 VPC 的计划，所以我这样做了
$ export AWS_PROFILE=myprofile …我想为安全组设置入口“Custome ICMP (IPv4)”规则，并且aws_security_group页面不清楚我需要为from_port和to_port值设置什么。它说（类似于to_port）
from_port - (Required) The start port (or ICMP type number if protocol is "icmp" or "icmpv6")
什么是ICMP type number？如果我在 AWS 控制台中手动执行此操作，则端口默认为N/A.
我有一个厨师服务器和运行带有最新补丁的RHEL 5.10的客户端VM。当我尝试以
knife bootstrap nodename -N nodename -x root -P password
我收到以下错误，这阻止了我的自动属性填充在服务器上。
nodename Converging 0 resources
nodename
nodename Running handlers:
nodename [2014-07-25T14:46:40-04:00] ERROR: Running exception handlers
nodename Running handlers complete
nodename
nodename [2014-07-25T14:46:40-04:00] ERROR: Exception handlers complete
nodename [2014-07-25T14:46:40-04:00] FATAL: Stacktrace dumped to /var/chef/cache/chef-stacktrace.out
nodename Chef Client failed. 0 resources updated in 3.383781 seconds
nodename [2014-07-25T14:46:40-04:00] ERROR: "\xC3" on US-ASCII
nodename [2014-07-25T14:46:40-04:00] FATAL: Chef::Exceptions::ChildConvergeError: Chef run process exited unsuccessfully (exit code 1)
这是引用的堆栈跟踪
Generated at 2014-07-25 15:01:29 -0400
Encoding::InvalidByteSequenceError: "\xC3" …更新后的描述更加清晰.
假设我有一个文件,其中包含这些行.
one
two
three
five
如何在显示"三"的行之后添加一行"四",这样我的文件现在看起来像这样？
one
two
three
four
five
我正在尝试获取某个图像的docker图像ID，所以我这样做
$ docker image ls
REPOSITORY TAG IMAGE ID CREATED SIZE
123456789012.dkr.ecr.us-east-1.amazonaws.com/some-name1 60 4a625fb9a2a4 5 hours ago 3.97GB
987654321012.dkr.ecr.us-east-1.amazonaws.com/some-other-name2 365 59b27e46effc 6 days ago 3.98GB
我希望这能给我图像ID，在这种情况下，即4a625fb9a2a4 ...
$ docker image ls | grep name1 | cut -d " " -f3
...但是没有，它给出了一个空白。我想念什么？
这个需求是一个简单的shell脚本，因此我可以将其嵌入到Jenkinsfile管道的Groovy脚本中。