当将NEWID()与持久计算列结合使用时,我得到奇怪的结果.我使用了一些功能错了吗?
在创建列时不使用持久化,因此在选择它们时计算值将返回正确的值.更新列(col1)也将返回正确的值.
DECLARE @test TABLE (
Col1 INT,
Contains2 AS CASE WHEN 2 IN (Col1) THEN 1 ELSE 0 END PERSISTED)
INSERT INTO @test (Col1) VALUES
(ABS(CHECKSUM(NEWID()) % 5)),
(ABS(CHECKSUM(NEWID()) % 5)),
(ABS(CHECKSUM(NEWID()) % 5)),
(ABS(CHECKSUM(NEWID()) % 5)),
(ABS(CHECKSUM(NEWID()) % 5))
SELECT * FROM @test
UPDATE @test SET Col1 = Col1*1
SELECT * FROM @test
/*
Col1 Contains2
2 0
2 0
0 1
4 0
3 0
Col1 Contains2
2 1
2 1
0 0
4 0
3 0 …Run Code Online (Sandbox Code Playgroud)