小编use*_*282的帖子

我正在使用几个月前安装的yii2版本.现在我希望它升级到最新版本.我如何知道正在使用哪个版本的Yii2以及如何升级到最新版本的yii2？

{} 在javascript 中表示什么？例如

 var txt={};

{} 意味着什么？

如何RBAC在Yii 2.0没有任何数据库的情况下实现.我将只有两个角色,即admin and author.我的RbacController是

<?php
namespace app\commands;

use Yii;
use yii\console\Controller;

class RbacController extends Controller
{
    public function actionInit()
    {
        $auth =  \Yii::$app->authManager;

        // add "createPost" permission
        $createPost = $auth->createPermission('createPost');
        $createPost->description = 'Create a post';
        $auth->add($createPost);

        // add "updatePost" permission
        $updatePost = $auth->createPermission('updatePost');
        $updatePost->description = 'Update post';
        $auth->add($updatePost);

        // add "author" role and give this role the "createPost" permission
        $author = $auth->createRole('author');
        $auth->add($author);
        $auth->addChild($author, $createPost);

        // add "admin" role and give this role the …

在Yii2中使用迁移功能,我试图添加一个'authorization_key'在表上调用的新列'users'.我的up功能如下:我的初始run功能就是这个

 public function up()
 {
     $this->createTable( 'users',   [
         'id' => 'pk',
          'username' => 'string UNIQUE',
          'password' => 'string'
     ]); 


  }

当我./yii migrate up 追赶时./yii migrate/create,桌子就被创建了.

但是在添加之后$this->addColumn('user', 'authorization_key'for', 'string UNIQUE');,即新up功能是

public function up()
     {
         $this->createTable( 'users',   [
             'id' => 'pk',
              'username' => 'string UNIQUE',
              'password' => 'string'
         ]); 

         $this->addColumn('user', 'authorization_key'for', 'string UNIQUE');
      }

然后我跑

 ./yii migrate up 

,它没有工作,并没有创建新专栏,但它显示

No new migration found. Your system is up-to-date. …

我的模型中的行为功能如下

public function behaviors()
    {
        return [
        'timestamp' => [
        'class' => 'yii\behaviors\TimestampBehavior',
        'attributes' => [
        ActiveRecord::EVENT_BEFORE_INSERT => ['log_in_time' ],
        ActiveRecord::EVENT_BEFORE_UPDATE => ['log_in_time'],
        ],
        'value' => new Expression('NOW()'),
        ],
        ];
    }
/**
     * validation rules
     */

public function rules()
{
    return [

            ['username','filter', 'filter' => 'trim'],
            ['username','required'],
            //['username','unique'],
            ['username','string', 'min' => 2, 'max' => 255],
            ['password','required'],

        ];
    }

/* Your model attribute labels */
public function attributeLabels()
{
    return [
    /* Your other attribute labels */
    ];
}

public function …

我正在使用标签导航到不同的视图。这些视图位于中'xype' container。我正在使用这样的功能来加载不同的视图

    Ext.getCmp('contactcontainer').setActiveItem(2);

但是我需要在调用新视图时消除滑动效果。怎么做到呢？我正在使用sencha touch 2

怎样才能yii\grid\ActionColumn的GridView::widget仅loggged在用户可见？我的代码是

<?= GridView::widget([
        'dataProvider' => $dataProvider,
        'filterModel' => $searchModel,
        'columns' => [
            ['class' => 'yii\grid\SerialColumn'],

            'state_id',
            'state_name',
            'population',
            'state_code',

            ['class' => 'yii\grid\ActionColumn'],
        ],
    ]); ?>

我有三张桌子

--
-- Table structure for table `tbl_ticket`
--

CREATE TABLE IF NOT EXISTS `tbl_ticket` (
`id` int(9) NOT NULL,
  `complain_id` varchar(250) CHARACTER SET latin1 NOT NULL,
  `section_id` varchar(250) CHARACTER SET latin1 NOT NULL,
  `location_id` varchar(250) CHARACTER SET latin1 NOT NULL,
  `status` varchar(250) CHARACTER SET latin1 NOT NULL,
  `remarks` varchar(250) CHARACTER SET latin1 NOT NULL,
  `r_date` datetime NOT NULL,
  `d_date` datetime NOT NULL,
  `hd_user_username` varchar(250) CHARACTER SET latin1 NOT NULL,
  `hd_user_email` varchar(250) CHARACTER SET latin1 NOT NULL,
  `description` varchar(250) NOT …

如何在Kartik Gridview中禁用分页？我正在使用如下代码

    echo GridView::widget([
        'dataProvider'=>$dataProvider,
        'filterModel'=>$searchModel,
        'showPageSummary'=>true,
            'responsive'=>true,

            'hover' => true,
         'pjax'=>true,
            'containerOptions'=>['style'=>'overflow: auto'], // only set when $responsive = false
            'headerRowOptions'=>['class'=>'kartik-sheet-style'],
            'filterRowOptions'=>['class'=>'kartik-sheet-style'],

        'striped'=>true,
        'hover'=>true,
            'pager' => [
                    'options'=>['class'=>'pagination'],   // set clas name used in ui list of pagination
                    'prevPageLabel' => 'Previous',   // Set the label for the "previous" page button
                    'nextPageLabel' => 'Next',   // Set the label for the "next" page button
                    'firstPageLabel'=>'First',   // Set the label for the "first" page button
                    'lastPageLabel'=>'Last',    // Set the label for the …

如何使用 jquery 或 javascript 删除所有出现的带有特定类的标签而不是其中的内容？例如以下必须转换

<a class="ab">
<ol>
<a class="ab">
<li><a class="ab">
abcde</a>
</li>

<li>
<a class="ab">
12354
</a>
</li>
</a>
</ol>
</a>

进入

 <ol>
    <li>
    abcde
    </li>
    <li>
    12354
    </li>
    </ol>

我想删除所有标签class= "ab"并保留其中的元素和内容