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导入javax.mail无法解析

import javax.mail.BodyPart;
import javax.mail.Message;
import javax.mail.MessagingException;
import javax.mail.Multipart;
import javax.mail.SendFailedException;
import javax.mail.Session;
import javax.mail.Transport;
import javax.mail.internet.InternetAddress;
import javax.mail.internet.MimeBodyPart;
import javax.mail.internet.MimeMessage;
import javax.mail.internet.MimeMultipart;    

private void sendMail() throws MessagingException{

    String host = "smtp.gmail.com";
    String password = "abcde12345";
    String from = "testing@gmail.com";
    String toAddress = email;
    String filename = Environment.getExternalStorageDirectory() + "/jam.jpg";

    Properties properties = System.getProperties();
    properties.put("mail.smtp.host", host);
    properties.put("mail.smtps.auth", true);
    properties.put("mail.smtp.starttls.enable", true);
    Session session = Session.getInstance(properties, null);

    MimeMessage message = new MimeMessage(session);
    message.setFrom(new InternetAddress(from));
    message.setRecipients(Message.RecipientType.TO, toAddress);
    message.setSubject("Anti-Theft Attachment");

    BodyPart messageBodyPart = new MimeBodyPart(); …
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java android

9
推荐指数
1
解决办法
5万
查看次数

我可以删除帐户并以编程方式在Android手机中同步吗?

我正在开发一个项目,需要远程删除帐户和同步,如Facebook,Twitter,Dropbox等......这是否可以通过编程完成?需要你们的意见......

谢谢.

android

7
推荐指数
1
解决办法
6020
查看次数

android.content.res.Resources $ NotFoundException

@Override
public void onCreate(Bundle savedInstanceState){

    super.onCreate(savedInstanceState);
    setContentView(R.layout.screenlocked);

    //Retrieve stored ID
    final String STORAGE = "Storage";  
    SharedPreferences unique = getSharedPreferences(STORAGE, 0);
    LoginID = unique.getString("identifier", "");

    //Retrieve stored phone number
    final String phoneNumber = unique.getString("PhoneNumber", "");
    phoneView = (TextView) findViewById(R.id.phone);
    phoneView.setText(phoneNumber.toString());

    //Retrieve user input
    input = (EditText) findViewById(R.id.editText1);
    userInput = input.getText().toString();

    //Set login button
    login = (Button) findViewById(R.id.login);
    login.setOnClickListener(new View.OnClickListener() {
        public void onClick(View view) {
            compareID();
        }
    });
}

public void compareID(){

    if (userInput.equals(LoginID)){
        //phone screen unlocked
        //continue
        Toast.makeText(ScreenLockActivity.this, "Success!", Toast.LENGTH_SHORT).show(); …
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java error-handling android

4
推荐指数
1
解决办法
8534
查看次数

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android ×3

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